callable

问题 I am new to Selenium/Python and practicing few exercises. I am receiving below error when running my Selenium/Python program in pycharm. Please help. C:\Users\rk.marav\PycharmProjects\RadhaSelenium\venv\Scripts\python.exe C:/Users/rk.marav/PycharmProjects/RadhaSelenium/Tests/mainTest.py Traceback (most recent call last): File "C:/Users/rk.marav/PycharmProjects/RadhaSelenium/Tests/mainTest.py", line 13, in <module> m.main() File "C:/Users/rk.marav/PycharmProjects/RadhaSelenium/Tests/mainTest

问题 I'm using pygame and I'm using a function that set the selected position of a text in PyGame : def textPos(YPos , TextSize): TextPosition.center(60,YPos) print("Size : " + TextSize) but when I run the program, I get an error: TextPosition.center(60,YPos) : TypeError : 'Tuple' object is not callable There's a way to solve this problem? 回答1: 'Tuple' object is not callable error means you are treating a data structure as a function and trying to run a method on it. TextPosition.center is a tuple

问题 I'm looking to get a result from a method which can take a while to complete and doesn't actually return the object, so I'd like to deal with it as effectively as possible. Here's an example of what I'm trying to achieve: public static void main (String[] args) { Object obj = someMethod(); System.out.println("The object is" + obj + ", wooh!"); } public void callObject() { // Sends request for the object } public void receiveObject(Object object) { // Received the object } public Object

问题 I am working on a project in which I have multiple interface and two Implementations classes which needs to implement these two interfaces. Suppose my first Interface is - public Interface interfaceA { public void abc() throws Exception; } And its implementation is - public class TestA implements interfaceA { // abc method } I am calling it like this - TestA testA = new TestA(); testA.abc(); Now my second interface is - public Interface interfaceB { public void xyz() throws Exception; } And

问题 I am working on a project in which I have multiple interface and two Implementations classes which needs to implement these two interfaces. Suppose my first Interface is - public Interface interfaceA { public void abc() throws Exception; } And its implementation is - public class TestA implements interfaceA { // abc method } I am calling it like this - TestA testA = new TestA(); testA.abc(); Now my second interface is - public Interface interfaceB { public void xyz() throws Exception; } And

问题 class Foo(object): def tick(self): print("something") class Bar(object): def __init__(self): self.foo = Foo() def tick(self): #Here's what I do.... self.foo.tick() #here's what my goal would be self.foo() b = Bar() b.tick() That's essentially my goal. From what I've gathered I could change the tick function to __call__ and that would allow me to do what I wanted. A couple of the other answers said that this would make a new instance of the object, does that mean that it would use self.foo's

问题 I somehow found the call() method is on every function. Using this method I could change my if (callback != null) callback() to callback?.call() . So I tried to find the implementation and document of call() , but I couldn't. Is it just built-in method? What will be the implementation of this method? Function.apply() will be called inside it? 回答1: All Dart functions (objects which has a function type rather than an class/interface type) have a call method. The call method has the same

问题 I somehow found the call() method is on every function. Using this method I could change my if (callback != null) callback() to callback?.call() . So I tried to find the implementation and document of call() , but I couldn't. Is it just built-in method? What will be the implementation of this method? Function.apply() will be called inside it? 回答1: All Dart functions (objects which has a function type rather than an class/interface type) have a call method. The call method has the same

问题 Here is the code: from typing import Any list = list(range(1, 41)) print(list) listValues = [] for i in range(1, 5): # 1,2,3,4 value = int(input("Digite o valor:" + str(i) + ":")) # Digite o valor listValues.append(value) print(value) for value in listValues: print(value) if value in list: print("Valor " + str(value) + " encontrado.") else: print("Valor " + str(value) + " não encontrado.") value = int(input("Digite o valor, para achar a posição:" +str(i) + ":")) pos = listValues.append(value)

问题 Here is the code: from typing import Any list = list(range(1, 41)) print(list) listValues = [] for i in range(1, 5): # 1,2,3,4 value = int(input("Digite o valor:" + str(i) + ":")) # Digite o valor listValues.append(value) print(value) for value in listValues: print(value) if value in list: print("Valor " + str(value) + " encontrado.") else: print("Valor " + str(value) + " não encontrado.") value = int(input("Digite o valor, para achar a posição:" +str(i) + ":")) pos = listValues.append(value)