cakephp-1.3

问题 I have been working on a CakePHP App, most of the CSS / JS / images (icons) are located in the webroot directory (/var/www/app/webroot/), but for some portion (Croogo) or other pages of the app, I need to load CSS / JS / images from a different directory i.e /var/www/app/views/themed/admin/webroot/. Now the issue I am facing is that when I render these other pages the css / JS / images requests return 404 page not found status, as these requests are made to main webroot rather than the

来源： https://stackoverflow.com/questions/63506815/cakephp-integrity-constraint-violation-1048-column-password-cannot-be-nu

问题 Can any one explain me the working of Auth->authorize = "actions" In my project i am planning tp give this. As this taught me the authorize will call the $this->Aro->check($user,"controllers/:controller/:action") This will check the against the user right?? that means the user should be there in aros table. But i don't need this to check against user but i need to check against a group How can i achive this. now when the users is not in Aro table it showing the So that The Aro's will be only

问题 I have a Mac running Mac OS X Leopard at work as well as at home and a PC at work as well. I have the project I'm currently working on set up on all 3, it works fine at my work computers but on my home Mac I get the error in the title. The project is on SVN so I just checked it out ran the SQL script for my DB schema and set up the same user I have in my work DB and it will not work still. I also cleared out the cache folders as suggested in other posts with a similar problem and it still won

问题 the following code is not able to hash the user's password, and it stores the password in clear text in the database. After changing the password, I am unable to log in as the password needs to be in hash. The following code is in my model. 'password_confirm'=>array( 'compare' => array( 'rule' => array('password_match', 'password', true), 'message' => 'Password does not match', 'required' => true, ), 'notempty' => array( 'rule' => array('notempty'), 'message' => 'Confirm password is empty',

问题 Using CakePHP 1.3 , I post a form which correctly fills in $this->data . According to the docs, it seems like $this->params['form'] should be populated with some information as well, but it's simply an empty array. Is there a particular reason for that? The form is built using the Form Helper, as follows... Some relevant code: $default_form_create_options = array( 'inputDefaults' => array( 'label'=>false, 'div'=>false ) ); echo $form->create('Preappform', $default_form_create_options); // ---

问题 In Component I try to access Myprofile Model class SignMeupComponent extends Object public function register() { $this->__isLoggedIn(); if (!empty($this->controller->data)) { extract($this->settings); $model = $this->controller->modelClass; $this->controller->loadModel($model); $this->controller->{$model}->Myprofile->save($this->controller->data); $this->controller->data['Myprofile']['user_id'] = $this->controller->{$model}->id; $this->controller->{$model}->set($this->controller->data); if (

问题 I'm looking to build a SQL query something like: "SELECT email.member_id, 1 FROM email ... " I'm using $this->Email->find('list', array( 'fields' => array('Email.member_id', '1'), ... CakePHP is generating: SELECT `Email`.`member_id`, `Email`.`1` FROM `emails` AS `Email` ... How do I specify that the 1 is a constant and not a database field? Why I want to do this I basically want to return an associative array with keys of member_id and values of 1. Would it be better to just get a straight

问题 I'm nearling completion of my first CakePHP-driven website and just saw they're already working on CakePHP 2.0 (not the stable release yet). My questions: Is it incredibly time consuming to move to a new version of CakePHP (when it becomes the "stable" release that is)? I know they have migration guides, but - I've never used a framework before, so I've never had to migrate anything. Do you migrate your code for existing projects, or leave it as is and use the new stable version for future

问题 I have the following codes, I added the debug and this is the data that I am able to retrieve from the database. I wish to display the ['User']['firstName'] and also the ['Passion']['passion_tag'] in the view page, how do I do it? I am facing error such as: Notice (8): Undefined index: passion_tag [APP\views\searches\simple_search.ctp, line 127] [5] => Array ( [User] => Array ( [id] => 41 [password] => 2b4a3cf55ddf9b15e161aeba3540a75ddd6ea872 [firstName] => Ming Xin [lastName] => Toh [email]