c#-4.0

How to share a connection string between multiple entity data model

删除回忆录丶 提交于 2020-02-01 04:17:05
问题 I have a project that has 4 entity data model.for building them I don't want save a connection string in my project and I want store a connection string in app.config files and share it between my models.How I can do this? thanks 回答1: Assuming DbContext and model/database first. Leave the generated EF connection strings in your app.config file intact. As Arthur said, they contain the paths to the EF metadata (csdl/ssdl/msl). They are also used during development by the model designer. Add a

NoSQL databases that officially support MonoTouch

旧巷老猫 提交于 2020-01-31 05:00:08
问题 I am having trouble finding a NoSQL databases that officially support MonoTouch via a local DB on the device. If their are, could someone provide a list of them here. 回答1: According to http://nosql-database.org/ there's siaqodb. Note that others might support MonoTouch without being mentioned in that site. Edit : a few more clicks shows that HSS Database (from the same list) also supports MonoTouch. You might also want to look at which ones support iOS (e.g. with Objective C) and see if

Difference between CLR 2.0 and CLR 4.0

断了今生、忘了曾经 提交于 2020-01-30 14:23:07
问题 I have read countless blogs, posts and StackOverflow questions about the new features of C# 4.0. Even new WPF 4.0 features have started to come out in the open. What I could not find and will like to know: What are the major changes to CLR 4.0 from a C#/WPF developer perspective? What are the major changes to CLR 4.0 as a whole? I think, internally, most changes are for the new dynamic languages and parallel programming. But are there any other major improvements? Because language

How to convert one type to another using reflection?

吃可爱长大的小学妹 提交于 2020-01-30 08:25:49
问题 I have a two types that are very similar (i.e. the member names are very similar). Is there an elegant way to copy one type to another, without having to copy each individual member by hand? Update Here is some sample source code: main() { FromCsvFile x = new FromCsvFile(fileName); OptionsEnt y = x.ToOptionsEnt(); // See helper function below. } // Chained helper function to convert type "FromCsvFile" to type "OptionsEnt". // Want to replace this with something more elegant (perhaps with

How to convert one type to another using reflection?

烈酒焚心 提交于 2020-01-30 08:25:31
问题 I have a two types that are very similar (i.e. the member names are very similar). Is there an elegant way to copy one type to another, without having to copy each individual member by hand? Update Here is some sample source code: main() { FromCsvFile x = new FromCsvFile(fileName); OptionsEnt y = x.ToOptionsEnt(); // See helper function below. } // Chained helper function to convert type "FromCsvFile" to type "OptionsEnt". // Want to replace this with something more elegant (perhaps with

How to convert one type to another using reflection?

坚强是说给别人听的谎言 提交于 2020-01-30 08:25:26
问题 I have a two types that are very similar (i.e. the member names are very similar). Is there an elegant way to copy one type to another, without having to copy each individual member by hand? Update Here is some sample source code: main() { FromCsvFile x = new FromCsvFile(fileName); OptionsEnt y = x.ToOptionsEnt(); // See helper function below. } // Chained helper function to convert type "FromCsvFile" to type "OptionsEnt". // Want to replace this with something more elegant (perhaps with

dynamic with ternary operator

跟風遠走 提交于 2020-01-30 07:12:21
问题 why and how this works in the below code dynamic x = ( c== 'a') ? new D1() :x= new D2(); but not this dynamic x = ( c== 'a') ? new D1() : new D2(); Code class Program { static void Main(string[] args) { var c = Console.ReadKey().KeyChar; dynamic x = ( c== 'a') ? new D1() :x= new D2(); x.Print(); Console.ReadKey(); } } class D1 { public void Print() { Console.WriteLine("D1"); } } class D2 { public void Print() { Console.WriteLine("D2"); } } 回答1: This has nothing to do with dynamic. This is

dynamic with ternary operator

落爺英雄遲暮 提交于 2020-01-30 07:11:35
问题 why and how this works in the below code dynamic x = ( c== 'a') ? new D1() :x= new D2(); but not this dynamic x = ( c== 'a') ? new D1() : new D2(); Code class Program { static void Main(string[] args) { var c = Console.ReadKey().KeyChar; dynamic x = ( c== 'a') ? new D1() :x= new D2(); x.Print(); Console.ReadKey(); } } class D1 { public void Print() { Console.WriteLine("D1"); } } class D2 { public void Print() { Console.WriteLine("D2"); } } 回答1: This has nothing to do with dynamic. This is

dynamic with ternary operator

生来就可爱ヽ(ⅴ<●) 提交于 2020-01-30 07:11:15
问题 why and how this works in the below code dynamic x = ( c== 'a') ? new D1() :x= new D2(); but not this dynamic x = ( c== 'a') ? new D1() : new D2(); Code class Program { static void Main(string[] args) { var c = Console.ReadKey().KeyChar; dynamic x = ( c== 'a') ? new D1() :x= new D2(); x.Print(); Console.ReadKey(); } } class D1 { public void Print() { Console.WriteLine("D1"); } } class D2 { public void Print() { Console.WriteLine("D2"); } } 回答1: This has nothing to do with dynamic. This is

What's the correct way of retrieving my custom enumeration classes by their value?

我与影子孤独终老i 提交于 2020-01-30 07:08:09
问题 I've created my own custom pseudo enumerations within my domain model to allow me to have some more verbose values. For example, my class is as follows: public abstract class Enumeration<X, Y> : IComparable where X : IComparable { public Enumeration(X value, Y displayName) { } public Y DisplayName { get { return _displayName; } } public X Value { get { return _value; } } } And a class that inherits it would be: public class JobType : Enumeration<string, string> { public static JobType