break | 易学教程

Break for loop in an if statement

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问题 Currently having trouble with breaking this for loop. I want to break it if the variable is not found in this list so it can move two another for loop. It expects an indented block for the top of the for loop, but if I change the position of the break or of the start of the for loop, it doesn't work. Help! while cyclenumb <= 10000: for x in userpassword[k]: for z in lowercaselist: if x in z: newpasswordlist.append(z) k +=1 break else: for x in userpassword[k]: for z in uppercaselist: if x in

break a loop if Esc was pressed

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问题 I have written a program in JAVA language which accepts inputs from console by using Scanner class.... now I want to add this ability to my code to exist a loop (while) when user presses Esc Button. so far I thought Keyboard class can help me but it was just like Scanner...I tried to use events but do not know how to use them correctly.... Source code: package switchCase_v1; import cs1.Keyboard; import java.util.EventObject; import java.awt.AWTEvent; import java.awt.event.KeyEvent; import

How do I exit a while loop in Java?

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问题 What is the best way to exit/terminate a while loop in Java? For example, my code is currently as follows: while(true){ if(obj == null){ // I need to exit here } } 回答1: Use break: while (true) { .... if (obj == null) { break; } .... } However, if your code looks exactly like you have specified you can use a normal while loop and change the condition to obj != null : while (obj != null) { .... } 回答2: while(obj != null){ // statements. } 回答3: break is what you're looking for: while (true) { if

较复杂的枚举类型

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1 package dataStyle; 2 /** 3 * 较复杂的枚举类型 4 * @author ZolRa 5 * 6 */ 7 public class ComEnum { 8 9 public static void main(String[] args) { 10 WeekDay weekDay = WeekDay.FRI; 11 System.out.println(weekDay.nextDay()); 12 } 13 14 public enum WeekDay{ 15 // 调用带参构造方法，匿名子类重写nextDay()方法 16 SUN( 1 ){ 17 public WeekDay nextDay() { 18 return MON; 19 } 20 }, 21 MON( 2 ){ 22 public WeekDay nextDay() { 23 return TUE; 24 } 25 }, 26 TUE( 3 ){ 27 public WeekDay nextDay() { 28 return WED; 29 } 30 }, 31 WED( 4 ){ 32 public WeekDay nextDay() { 33 return THU; 34 } 35 }, 36 THU( 5 ){ 37 public WeekDay nextDay() { 38

switch中default的用法

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default什么时候会执行？default的位置对执行结果有影响吗？ default只有在case匹配失败的时候才会执行 int a=4; switch (a){ case 1: System.out.println("1"); break; case 2: System.out.println("2"); break; case 3: System.out.println("3"); break; default: System.out.println("default"); break; 打印结果：default 当然也有特殊情况，就是case匹配成功了，但缺少了break语句 int a=3; switch (a){ case 1: System.out.println("1"); break; case 2: System.out.println("2"); break; case 3: System.out.println("3"); default: System.out.println("default"); break; 打印结果： 3 default default的位置对执行结果有没有影响，关键看default有没有使用break，先看有break的情况下是什么结果 int a=4; switch (a){ default: System.out

BREAK in AWK doesn't work

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问题 I have: AGT GTT TTA CAT TTT GTA TTT TTT TTC TAA ATT CTG AGT GTA GTC TTC CCT My desired output is: AGT GTT TTA CAT TTT My code: awk '{for (i=1;i<=NF;i++) {printf $i" "; if ($i~/TTT/) {break}}}' However, it seems that break doesn't work cause it prints: AGT GTT TTA CAT TTT GTA TTT TTT TTC TAA ATT CTG AGT GTA GTC TTC CCT 回答1: As indicated on the comments, changing break for exit can make it: awk '{for (i=1;i<=NF;i++) {printf $i" "; if ($i~/TTT/) exit}}' file Note you can delete the brackets

Break Out of then promises in Angularjs

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问题 I am trying to find a way to break out of a promise chain in AngularJS code. The obvious way was to return an object and then check is validity in every "then" function in the chain. I would like to find a more elegant way of breaking out of a then chain. 回答1: In angular, there is the $q service that can be injected in directives, controllers etc, that is a close implentation of Kris Kowal's Q. So inside of then function instead of returning a value or something else that would be chained to

Killing a For loop in Julia array comprehension

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问题 I have the following line of code in Julia: X=[(i,i^2) for i in 1:100 if i^2%5==0] Basically, it returns a list of tuples (i,i^2) from i=1 to 100 if the remainder of i^2 and 5 is zero. What I want to do is, in the array comprehension, break out of the for loop if i^2 becomes larger than 1000 . However, if I implement X=[(i,i^2) for i in 1:100 if i^2%5==0 else break end] I get the error: syntax: expected "]" . Is there any way to easily break out of this for loop inside the array? I've tried

Python: merging tally data

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问题 Okay - I'm sure this has been answered here before but I can't find it.... My problem: I have a list of lists with this composition 0.2 A 0.1 A 0.3 A 0.3 B 0.2 C 0.5 C My goal is to output the following: 0.6 A 0.3 B 0.7 C In other words, I need to merge the data from multiple lines together. Here's the code I'm using: unique_percents = [] for line in percents: new_percent = float(line[0]) for inner_line in percents: if line[1] == inner_line[1]: new_percent += float(inner_line[0]) else: temp =

How to stop inner and outer loop using break statement [duplicate]

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问题 This question already has answers here : Can I use break to exit multiple nested for loops? (18 answers) Closed 4 years ago . I have really simple code where I use break inside inner loop: for (int it=0; it<5; it++) { for (int it2=0; it2<5; it2++) { if (it2==2) break; //break here not it2, but it loop NSLog(@"it=%d it2=%d", it, it2); } } I receive an output: it=0 it2=0, it=0 it2=1, it=1 it2=0, it=1 it2=1, it=2 it2=0, it=2 it2=1, it=3 it2=0, it=3 it2=1, it=4 it2=0, it=4 it2=1 I know in some