boxplot

How do I show all boxplot labels

风流意气都作罢 提交于 2021-02-16 04:21:46
问题 I've created a box plot, the data on the left is the continous variable and the data on the right has about 10 unique options. When I create the boxplot I cannot see the labels. How do I make it show all the labels, possibly vertically? boxplot(data$Rate ~ as.factor(data$Purpose)) I've looked around and cannot work out what im trying to follow. 回答1: You can add argument las=2 to function boxplot() to make all labels perpendicular to axis. df<-data.frame(Rate=rnorm(100),Purpose=rep(letters[1

How do I show all boxplot labels

对着背影说爱祢 提交于 2021-02-16 04:20:26
问题 I've created a box plot, the data on the left is the continous variable and the data on the right has about 10 unique options. When I create the boxplot I cannot see the labels. How do I make it show all the labels, possibly vertically? boxplot(data$Rate ~ as.factor(data$Purpose)) I've looked around and cannot work out what im trying to follow. 回答1: You can add argument las=2 to function boxplot() to make all labels perpendicular to axis. df<-data.frame(Rate=rnorm(100),Purpose=rep(letters[1

In a single figure, boxplot of all columns split by a “label” column

六眼飞鱼酱① 提交于 2021-02-08 07:35:27
问题 Looking at the boxplot API page, I want something that looks like a combination of this: >>> iris = sns.load_dataset("iris") >>> ax = sns.boxplot(data=iris, orient="h", palette="Set2") Except I want it split by a column that holds a certain label, similarly to what is achieved by the hue argument in an example that follows: ax = sns.boxplot(x="day", y="total_bill", hue="smoker", data=tips, palette="Set3") This example only works when x and y are defined, but for what I want to achieve I want

Boruta box plots in R

若如初见. 提交于 2021-02-07 23:59:11
问题 I'm doing variable selection with the Boruta package in R. Boruta gives me the standard series of boxplots in a single graph, which is useful, but given the fact that I have too many predictors, I am hoping to be able to limit the number of boxplots that appear in the boruta plot. Something like the following image. Basicacly, I want to "zoom" on the right end of the plot, but have no idea how to do that with the boruta plot object. Thanks, MR 回答1: Sounds like an simple question, the solution

Boruta box plots in R

邮差的信 提交于 2021-02-07 23:57:47
问题 I'm doing variable selection with the Boruta package in R. Boruta gives me the standard series of boxplots in a single graph, which is useful, but given the fact that I have too many predictors, I am hoping to be able to limit the number of boxplots that appear in the boruta plot. Something like the following image. Basicacly, I want to "zoom" on the right end of the plot, but have no idea how to do that with the boruta plot object. Thanks, MR 回答1: Sounds like an simple question, the solution

Boruta box plots in R

女生的网名这么多〃 提交于 2021-02-07 23:57:11
问题 I'm doing variable selection with the Boruta package in R. Boruta gives me the standard series of boxplots in a single graph, which is useful, but given the fact that I have too many predictors, I am hoping to be able to limit the number of boxplots that appear in the boruta plot. Something like the following image. Basicacly, I want to "zoom" on the right end of the plot, but have no idea how to do that with the boruta plot object. Thanks, MR 回答1: Sounds like an simple question, the solution

Violinplot in R with discrete values

好久不见. 提交于 2021-02-07 20:52:31
问题 I'm trying to create a violin plot in R from count data. The data I use is a number of mutations that is found in each sample for each source. It looks something like this: 2 Source1 8 Source2 0 Source1 1 Source1 9 Source2 ... I already used the code below to create several plots. ggplot(df_combined, aes(factor(names), y=mutations)) + geom_violin() + geom_boxplot(width=.1, outlier.size=0, fill="grey50") + stat_summary(fun.y=median, geom="point", fill="white", shape=21, size=4) + xlab("Source"

Violinplot in R with discrete values

拟墨画扇 提交于 2021-02-07 20:48:42
问题 I'm trying to create a violin plot in R from count data. The data I use is a number of mutations that is found in each sample for each source. It looks something like this: 2 Source1 8 Source2 0 Source1 1 Source1 9 Source2 ... I already used the code below to create several plots. ggplot(df_combined, aes(factor(names), y=mutations)) + geom_violin() + geom_boxplot(width=.1, outlier.size=0, fill="grey50") + stat_summary(fun.y=median, geom="point", fill="white", shape=21, size=4) + xlab("Source"

ggplot2 - Multiple Boxplots from Sources of Different Lengths

对着背影说爱祢 提交于 2021-02-07 06:26:04
问题 I have a few different vectors of varying length for which I would like to generate side by side boxplots using ggplot2. This is relatively straight forward to do with the Base plotting system. However ggplot2 only takes a single data frame as input, which is difficult to create from data of varying lengths. a <- rnorm(10) b <- rnorm(100) c <- rnorm(1000) boxplot(a, b, c) Q: What is the correct way to draw boxplots using ggplot2 using data of varying lengths? 回答1: ggplot uses tidy long data

ggplot2 - Multiple Boxplots from Sources of Different Lengths

不羁的心 提交于 2021-02-07 06:25:46
问题 I have a few different vectors of varying length for which I would like to generate side by side boxplots using ggplot2. This is relatively straight forward to do with the Base plotting system. However ggplot2 only takes a single data frame as input, which is difficult to create from data of varying lengths. a <- rnorm(10) b <- rnorm(100) c <- rnorm(1000) boxplot(a, b, c) Q: What is the correct way to draw boxplots using ggplot2 using data of varying lengths? 回答1: ggplot uses tidy long data