boolean-operations

问题 I'm adding a pair of unsigned 32bit binary integers (including overflow). The addition is expressive rather than actually computed, so there's no need for an efficient algorithm, but since each component is manually specified in terms of individual bits, I need one with a compact representation. Any suggestions? Edit: In terms of boolean operators. So I'm thinking that carry = a & b; sum = a ^ b; for the first bit, but the other 31? Oh, and subtraction! 回答1: You can not perform addition with

问题 I am little confused with logical AND operator. I have these 2 lines of code. Here num and j are both int. I have a situation where both the conditions are satisfied, but I don't know why it's not printing the value of j . Can anybody point out the mistakes? Thanks in advance. if(k==1 && num%j==0) printf("%d",j); 回答1: In plain English, the expression k == 1 && num % j == 0 is true if and only if k equals 1 and the remainder from dividing num by j is 0. Not much more I can say. 回答2: There's

问题 I got frustated with my other question. So i wrote up this example. In C the below is true. See demo int main() { printf("%d", 1 && 2); return 0; } Output: 1 In C#. It is FALSE. WHY is this false? Also i dont understand why i needed to create the bool operator in this example but not the one in my other question but no matter. Why is the below false? it makes no sense to me. BTW the logic making the below false is described here using System; using System.Collections.Generic; using System

问题 I want to control the execution of a function using a placeholder, but keep getting an error "Using a tf.Tensor as a Python bool is not allowed". Here is the code that produces this error: import tensorflow as tf def foo(c): if c: print('This is true') #heavy code here return 10 else: print('This is false') #different code here return 0 a = tf.placeholder(tf.bool) #placeholder for a single boolean value b = foo(a) sess = tf.InteractiveSession() res = sess.run(b, feed_dict = {a: True}) sess

问题 Does Matlab have a Boolean (sometimes called logical or binary) matrix multiplication function? I'm specifically talking about what's usually denoted by a circle with a dot in it to denote Boolean matrix multiplication: cij = (ai1 & b1j) || (ai2 & b2j) || (ai3 & b3j)|| ... || (aik & bkj) I have had a hard time locating one and am now assuming one does not exist. If that is the case, is there a quick way to write a .m file that will accomplish this task? An example would be: [1 1 1; [1 0 1; [1

问题 I wrote a function to compare file versions between what a client currently has and the latest version of the file on a server. The client passes the "quad" (Major.Minor.Build.Private) version number as a string to the server, and then the server uses FileVersionInfo: // clientFileVersion will be in "quad" format, a la "3.1.4.1" private bool ServerFileIsNewer(string clientFileVersion, FileVersionInfo serverFile) { // Don't say I never learned nuthin' from Steve McConnell const int MAJOR_INDEX

问题 In three.js there is a function triangulateShape() . Now I encountered a failure to triangulate polygons that are simplified using Javascript Clipper. Simplifying in Clipper is done using Unioning. Wikipedia article determines unioning as finding the simple polygon or polygons containing the area inside either of two simple polygons. The same article says that in simple polygon "exactly two edges meet at each vertex" and also determines a weakly simple polygon, where edges can meet, but says

问题 Is it really a good practice to avoid using NOT operator in IF conditions in order to make your code better readable? I heard the if (doSomething()) is better then if (!doSomething()). 回答1: It really depends on what you're trying to accomplish. If you have no else clause then if(!doSomething()) seems fine. However, if you have if(!doSomething()) { ... } else { // do something else } I'd probably reverse that logic to remove the ! operator and make the if clause slightly more clear. 回答2: As a

问题 Assuming 2 gate-delays for a Sum or Carry function, estimate the time for ripple-through carry addition for adders with the following word lengths:- i) 4-bit ii) 8-bit iii) 16-bit In my notes I have written: "delay is the word width times each bit stage delay (2 gate delays)". Therefore: i) 2*4 = 8 ii) 2*8 = 16 iii) 2*16 = 32 Looking at the ripple carry adder wikipedia page: http://en.wikipedia.org/wiki/Ripple_carry_adder#Ripple-carry_adder The formula used here is different, can anyone

问题 I am working with Room persistent database in my project. I have a table in which there is a column for Boolean values as in 0 or 1, now i want the count of all Boolean values whose value is true (or 1). I know that i can achieve this using select query by getting the count of all selected rows using where clause! But i don't want to use Select query with where clause for this because it will load all the rows and then i will get the count, but i want the count without loading any rows!