bins

Matplotlib histogram with collection bin for high values

痞子三分冷 提交于 2019-12-02 18:08:44
I have an array with values, and I want to create a histogram of it. I am mainly interested in the low end numbers, and want to collect every number above 300 in one bin. This bin should have the same width as all other (equally wide) bins. How can I do this? Note: this question is related to this question: Defining bin width/x-axis scale in Matplotlib histogram This is what I tried so far: import matplotlib.pyplot as plt import numpy as np def plot_histogram_01(): np.random.seed(1) values_A = np.random.choice(np.arange(600), size=200, replace=True).tolist() values_B = np.random.choice(np

R: Control number of histogram bins

☆樱花仙子☆ 提交于 2019-12-02 17:44:00
问题 I am using the hist-function to analyze some data I generated. For an analysis-assay I would like to precisely control the number of histogram bins. I know the "break-argument" and I can see that in many cases the number of bins is in a direct relationship to the number of breaks (i.e. no_bins = no_breaks + 1). Due to R's algorithm this is not always the case. Is there a way to force R to output a specific number of bins? Let me know if I need to specify further details. Best and many thanks!

R: Control number of histogram bins

旧时模样 提交于 2019-12-02 08:26:24
I am using the hist-function to analyze some data I generated. For an analysis-assay I would like to precisely control the number of histogram bins. I know the "break-argument" and I can see that in many cases the number of bins is in a direct relationship to the number of breaks (i.e. no_bins = no_breaks + 1). Due to R's algorithm this is not always the case. Is there a way to force R to output a specific number of bins? Let me know if I need to specify further details. Best and many thanks! From ?hist , there are several options for controlling the bins through the breaks argument. breaks

Histogram with logarithmic bins and normalized

混江龙づ霸主 提交于 2019-12-01 14:33:25
I want to make a histogram of every column of a matrix, but I want the bins to be logarithmic and also normalized. And after I create the histogram I want to make a fit on it without showing the bars. This is what I have tried: y=histogram(x,'Normalized','probability'); This gives me the histogram normalized, but I don't know how to make the bins logarithmic. There are two different ways of creating a logarithmic histogram: Compute the histogram of the logarithm of the data. This is probably the nicest approach, as you let the software decide on how many bins to create, etc. The x-axis now

Histogram with logarithmic bins and normalized

荒凉一梦 提交于 2019-12-01 12:58:13
问题 I want to make a histogram of every column of a matrix, but I want the bins to be logarithmic and also normalized. And after I create the histogram I want to make a fit on it without showing the bars. This is what I have tried: y=histogram(x,'Normalized','probability'); This gives me the histogram normalized, but I don't know how to make the bins logarithmic. 回答1: There are two different ways of creating a logarithmic histogram: Compute the histogram of the logarithm of the data. This is

R code to categorize age into group/ bins/ breaks

旧城冷巷雨未停 提交于 2019-11-27 04:32:49
I am trying to categorize age into group so it will not be continuous. I have this code: data$agegrp(data$age>=40 & data$age<=49) <- 3 data$agegrp(data$age>=30 & data$age<=39) <- 2 data$agegrp(data$age>=20 & data$age<=29) <- 1 the above code is not working under survival package. It's giving me: invalid function in complex assignment Can you point me where the error is? data is the dataframe I am using. A5C1D2H2I1M1N2O1R2T1 I would use findInterval() here: First, make up some sample data set.seed(1) ages <- floor(runif(20, min = 20, max = 50)) ages # [1] 27 31 37 47 26 46 48 39 38 21 26 25 40