binary-tree

Plot of BinaryTree (ctree, party) ignores plot option of par()

安稳与你 提交于 2020-08-07 05:06:13
问题 I would like to plot the BinaryTree in the uppper part of the plot, and make a second one in the second part (bottom). Here is some example code to show, that the plot of the tree completely ignores the partitioning options set by par() library("party") ### regression airct <- ctree(Ozone ~ ., data = subset(airquality, !is.na(Ozone))) ### classification irisct <- ctree(Species ~ .,data = iris) par(mfrow = c(2, 1)) plot(airct) plot(irisct) This code does not plot the two trees in the same plot

What is the time complexity of deleting a node in a binary tree

坚强是说给别人听的谎言 提交于 2020-08-06 14:54:06
问题 For deleting a node in the binary tree, we have to search the node. That is possible in minimum O(log N) and max O(N). Depending on the node, we have to rearrange the pointers. How do we calculate the time complexity of that. 回答1: That depends on how you're doing the deletion. The most common way involves finding the successor of the node, then replacing the node with that successor. This can be done in O(h), where h is the height of the tree. In the worst case this is O(n), but in a balanced

Building a Binary Tree (not BST) in Haskell Breadth-First

旧时模样 提交于 2020-07-17 06:53:33
问题 I recently started using Haskell and it will probably be for a short while. Just being asked to use it to better understand functional programming for a class I am taking at Uni. Now I have a slight problem I am currently facing with what I am trying to do. I want to build it breadth-first but I think I got my conditions messed up or my conditions are also just wrong. So essentially if I give it [“A1-Gate”, “North-Region”, “South-Region”, “Convention Center”, “Rectorate”, “Academic Building1”

Building a Binary Tree (not BST) in Haskell Breadth-First

浪尽此生 提交于 2020-07-17 06:53:20
问题 I recently started using Haskell and it will probably be for a short while. Just being asked to use it to better understand functional programming for a class I am taking at Uni. Now I have a slight problem I am currently facing with what I am trying to do. I want to build it breadth-first but I think I got my conditions messed up or my conditions are also just wrong. So essentially if I give it [“A1-Gate”, “North-Region”, “South-Region”, “Convention Center”, “Rectorate”, “Academic Building1”

deleting a node from a binary search tree using recursion

点点圈 提交于 2020-06-17 09:10:02
问题 So I'm trying to delete a node from a tree by using these two functions inside the class.Unfortunately it just doesnt delete anything and i was wondering what is wrong about it! any help would be truly appreciated. def Find_Min(self,node): current=node while current.left is None: current=current.left return current def deletenode(self,node,ntbd): ##ntbd:node to be deleted /// node: root node if node is None: return None elif node.data>ntbd: node.left=self.deletenode(node.left,ntbd) elif node

deleting a node from a binary search tree using recursion

筅森魡賤 提交于 2020-06-17 09:09:33
问题 So I'm trying to delete a node from a tree by using these two functions inside the class.Unfortunately it just doesnt delete anything and i was wondering what is wrong about it! any help would be truly appreciated. def Find_Min(self,node): current=node while current.left is None: current=current.left return current def deletenode(self,node,ntbd): ##ntbd:node to be deleted /// node: root node if node is None: return None elif node.data>ntbd: node.left=self.deletenode(node.left,ntbd) elif node

How to transform list of hierarchyid into a binary tree

蓝咒 提交于 2020-06-14 06:33:46
问题 I am working on a multi-level marketing (binary) which looks like this: (but the binary tree is not required to be perfect. A node can have 0-2 child) My problem is the data that I fetch from the database is flat list. Notice that I am using hierarchyid (sql server 2014) Basically the TextNode column is like a breadcrumb. every slash / represents a level . If I have TextNode of /1/ as root. then every node that starts with /1/ belongs to that root which are /1/ , /1/1/ and /1/1/1/ (the root

How to transform list of hierarchyid into a binary tree

匆匆过客 提交于 2020-06-14 06:33:09
问题 I am working on a multi-level marketing (binary) which looks like this: (but the binary tree is not required to be perfect. A node can have 0-2 child) My problem is the data that I fetch from the database is flat list. Notice that I am using hierarchyid (sql server 2014) Basically the TextNode column is like a breadcrumb. every slash / represents a level . If I have TextNode of /1/ as root. then every node that starts with /1/ belongs to that root which are /1/ , /1/1/ and /1/1/1/ (the root

Find Path to Specified Node in Binary Tree (Python)

删除回忆录丶 提交于 2020-06-12 22:09:16
问题 I'm having trouble computing the path from the root to a specified node in a binary tree (this is specifically about a Python solution to this problem). Here's an example. Given the binary tree below, if I specify the node whose value is 4, I want to return [1, 2, 4]. If I specify the node whose value is 5, I want to return [1, 2, 5]. 1 / \ 2 3 / \ 4 5 Here's my attemped solution. class TreeNode: def __init__(self, x): self.val = x self.left = None self.right = None def path(root, k, l=[]):