bearing

Calculate bearing between 2 points with javascript

由 孤街醉人 提交于 2019-12-12 20:38:07
问题 I want to calculate the bearing from point 1 to point 2 The input format is 52.070564 - 4.407116 No matter what i try i cannot get an correct output. The formula i use is : // koers berekenen var y = Math.sin(ln-ln1) * Math.cos(lt); var x = Math.cos(lt1)*Math.sin(lt) - Math.sin(lt1)*Math.cos(lt)*Math.cos(ln-ln1); var radians = Math.atan2(y, x); var bearing = Math.round(radians * (180/Math.PI)); /* >>>>>> original <<<<<<< var y = Math.sin(λ2-λ1) * Math.cos(φ2); var x = Math.cos(φ1)*Math.sin(φ2

Need a sector based on bearing, geopoint, distance and angle

由 依然范特西╮ 提交于 2019-12-12 04:44:01
问题 I have a problem. I am trying to write a JAVA code were in given bearing, (lat,lon) , speed I need to get all points which form a sector (like in the diagram (x1,y1) , (x2,y2) and list of points which form an Arc in the direction which is given by bearing (I have very limited knowledge on bearing). My first thing is to achieve sector based on the direction with hard-coded distance and angle. (i.e fixed values say d = 5km and angle = 60 deg .) Next Step is based on the speed I want distance d

Find nearest bearing on compass going both directions; into existing formula

由 邮差的信 提交于 2019-12-11 05:16:49
问题 Mandar has graciously written this code for me from this Q/A in r, how to assess the two vectors based on other vectors names(df) <- c("a","b","c","d") df_backup <- df df$newcol <- NA used <- c() for (i in seq(1,length(df$a),1)){ print("######## Separator ########") print(paste("searching right match that fits criteria for ",df$a[i],"in column 'a'",sep="")) valuea <- df[i,1] orderx <- order(abs(df$b-valuea)) index=1 while (is.na(df$newcol[i])) { j=orderx[index] if (df$b[j] %in% used){ print

FInd latitude longitude point in php given initial lat lng, distance, and bearing

由 爱⌒轻易说出口 提交于 2019-12-07 03:35:46
问题 In php, given a latitude and longitude point, a bearing (in degrees), and a distance (in feet or km or whatever) how do I figure out what the new lat lng point is? here is what I tried, but it's wrong. function destinationPoint($lat, $lng, $brng, $dist) { $meters = $dist/3.2808399; // dist in meters $dist = $meters/1000; // dist in km $rad = 6371; // earths mean radius $dist = $dist/$rad; // convert dist to angular distance in radians $brng = deg2rad($brng); // conver to radians $lat1 =

How to visualise an arrow pointing to a certain coordinates(latitude, longitude), given pich and yaw

由 霸气de小男生 提交于 2019-12-06 12:37:21
问题 I would like to know how to visualise an arrow pointing to a certain coordinates(latitude, longitude) while I'm moving around holding my handset. I'va calculated the pitch and yaw of the desired position. Now I want to know how to keep pointing to this position while moving. Regards, 回答1: In general you can calculate the bearing angle (the angle between your local meridian and the great circle connecting your current position and the target position measured from the north direction) using

FInd latitude longitude point in php given initial lat lng, distance, and bearing

由 泄露秘密 提交于 2019-12-05 07:04:02
In php, given a latitude and longitude point, a bearing (in degrees), and a distance (in feet or km or whatever) how do I figure out what the new lat lng point is? here is what I tried, but it's wrong. function destinationPoint($lat, $lng, $brng, $dist) { $meters = $dist/3.2808399; // dist in meters $dist = $meters/1000; // dist in km $rad = 6371; // earths mean radius $dist = $dist/$rad; // convert dist to angular distance in radians $brng = deg2rad($brng); // conver to radians $lat1 = deg2rad($lat); $lon1 = deg2rad($lng); $lat2 = asin(sin($lat1)*cos($dist) + cos($lat1)*sin($dist)*cos($brng)

Using Compass to point to actual coordinate location instead of just North

由 泪湿孤枕 提交于 2019-12-04 16:53:02
I have seen a few examples of this but am not sure exactly how to implement it, (such as iPhone Compass GPS Direction ) in do I need to call calcBearingWithLatitude in (void)startup? All I am trying to do is have the compass pull a point from memory and use that point as its "north" so to speak and point to it, no need for distance or anything like that. My implementation file as of now looks like @implementation TrackerViewController @synthesize locationManager; @synthesize compass; @synthesize headingLabel; - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; if (

calculating a gps coordinate given a point, bearing and distance

由 烈酒焚心 提交于 2019-12-03 10:17:50
问题 I have a problem which draws my back in some project for some time now. Im basically looking to trap a polygon using x,y points drawn by some script ive written. lat1,lon1 are the center gps cords of the polygon and im looking for its surrounding polygon. here is a part of my code in python: def getcords(lat1,lon1,dr,bearing): lat2=asin(sin(lat1)*cos(dr)+cos(lat1)*sin(dr)*cos(bearing)) lon2=lon1+atan2(sin(bearing)*sin(dr)*cos(lat1),cos(dr)-sin(lat1)*sin(lat2)) return [lat2,lon2] my input goes

calculating a gps coordinate given a point, bearing and distance

由 会有一股神秘感。 提交于 2019-12-03 00:48:24
I have a problem which draws my back in some project for some time now. Im basically looking to trap a polygon using x,y points drawn by some script ive written. lat1,lon1 are the center gps cords of the polygon and im looking for its surrounding polygon. here is a part of my code in python: def getcords(lat1,lon1,dr,bearing): lat2=asin(sin(lat1)*cos(dr)+cos(lat1)*sin(dr)*cos(bearing)) lon2=lon1+atan2(sin(bearing)*sin(dr)*cos(lat1),cos(dr)-sin(lat1)*sin(lat2)) return [lat2,lon2] my input goes like this: lat1,lon1 - are given in decimal degrees. -dr is the angular computed by dividing the

How to compute hypotenuse and bearing

由 蹲街弑〆低调 提交于 2019-12-02 19:29:29
问题 I got the below code from @DanS at this link how-to-display-a-map-still-image-file-with-a-moving-current-location onCurrentPosition(Location current){ double hypotenuse = upperLeft.distanceTo(current); double bearing = upperLeft.bearingTo(current); double currentDistanceX = Math.cos(bearing) * hypotenuse; // "percentage to mark the position" double currentPixelX = (currentDistanceX / upperLeft.distanceTo(lowerRight) * Math.cos(upperLeft.bearingTo(lowerRight))) * mapWidth; moveIndicatorX
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