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I'm trying to close my app on a back button click. From the main screen, the back button takes you to a credits screen. From that credits screen, I want to close the app with the back button. Unfortunately, the onBackPressed() method I'm calling doesn't seem to be executed at all. I'm not sure how to proceed. package app.jonward.boss; import android.app.Activity; public class Credits extends Activity{ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.credits); //Doing stuff } @Override public void onBackPressed() { finish();

I have a click that changes things on the page when you click it. I was wondering if there was a way to trigger an effect when you press the back button on the browser You can sort of do it using the popstate event: window.onpopstate = function() { alert("pop!"); } or in jQuery : $(window).on('popstate', function(event) { alert("pop"); }); However this will also trigger when navigating forward, not only backward. Disable back url $(function() { if (window.history && window.history.pushState) { window.history.pushState('', null, './'); $(window).on('popstate', function() { // alert('Back button

Basically, I have a page that contains a form. When a user submits that form, a Javscript function is called and the user is dynamically presented with a new form. At this point, what I would like is for the user to be able to click the browser's back button and be taken back to the first form. Is this possible? Thanks for the quick responses, but I am having trouble getting pushState to work. The HTML still displays "second form" after I click the back button. Here is the code I used to test it: <script> function newPage(){ history.pushState({state:1}, "State 1", "?state=1"); document

I need to disable the back button of browser in my single page application. I tried using methods like onhashchange or window.history.forward but they don't work (reason may be that url doesn't get changed here) Please help! Thanks. I work in AngularJS building a Single Page App and I wanted to disable or prevent the back button of the browser, because my app has buttons and anchors for all navegation into my app. I searched and test many codes, and this is the easy to prevent the back button of browsers and the following code worked for me. window.onpopstate = function (e) { window.history

1· Activity的生命周期（一） 1.1 如何定义多个Activity 1 - 新建一个类，继承Activity package com.example.activiylife; import android.app.Activity; public class SecondActivity extends Activity{ } 2- 重写Activity中的onCreate方法 protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); } 3- 创建布局文件： <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <TextView android:id="@+id/textView" android:layout_width="wrap_content" android

I would like to detect when a user is about to exit the page, before they click the back button , and do something - for example display a popup. I do not want to prevent the user from leaving the page, but only to grab their attention again. This is already done by Optin Monster , but I want to implement it myself. Where to start? Edit: beforeunload is fired after the user clicked the back or x button. I would like to catch his exit intent , for example when the mouse is moving towards the back button, but before it was clicked. A. Wolff Ouibounce does this. There is a live demo here . npm

I want the users of my android app to leave my app when they press back at a certain activity. Can this be done? You can try something like this (shows a dialog to confirm exit): @Override public void onBackPressed() { new AlertDialog.Builder(this).setIcon(android.R.drawable.ic_dialog_alert).setTitle("Exit") .setMessage("Are you sure you want to exit?") .setPositiveButton("Yes", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { finish(); System.exit(0); } }).setNegativeButton("No", null).show(); } It must be noted as it is mentioned in