arrays

问题 How do I combine these arrays with the outcome of (2, 4, 5, 3, 7, 6) ? array1 = Array(4,5,3,7,6) array2 = Array(2) 回答1: You could potentially Join() and concatenate your two arrays, and then Split() the result back to a new array: array3 = Split(Join(array2, ",") & "," & Join(array1, ","), ",") Explanation: Join() will return a string that has each element in the array (first parameter) delimited by a "," (second parameter). We concatenate those two joined arrays with one more comma to get a

问题 I have array of strings const arr = ['some', 'word', 'anotherverylongword', 'word', 'yyy', 'u'] const joined = arr.join(';') I want to get array of chunks where joined string length is not greater than 10 for example output would be: [ ['some;word'], // joined string length not greater than 10 ['anotherverylongword'], // string length greater than 10, so is separated ['word;yyy;u'] // joined string length is 10 ] 回答1: You can use reduce (with some spread syntax and slice) to generate such

问题 I have array of strings const arr = ['some', 'word', 'anotherverylongword', 'word', 'yyy', 'u'] const joined = arr.join(';') I want to get array of chunks where joined string length is not greater than 10 for example output would be: [ ['some;word'], // joined string length not greater than 10 ['anotherverylongword'], // string length greater than 10, so is separated ['word;yyy;u'] // joined string length is 10 ] 回答1: You can use reduce (with some spread syntax and slice) to generate such

问题 Recently, I had to work on optimising a task that involved the creation of really large arrays (~ 10⁸ elements). I tested a few different methods, and, according to jsperf, the following option seemed to be the fastest. var max = 10000000; var arr = new Array(max); for (let i = 0; i < max; i++) { arr[i] = true; } Which was ~ 85% faster than var max = 10000000; var arr = []; for (let i = 0; i < max; i++) { arr.push(true); } And indeed, the first snippet was much faster in my actual app as well

问题 Recently, I had to work on optimising a task that involved the creation of really large arrays (~ 10⁸ elements). I tested a few different methods, and, according to jsperf, the following option seemed to be the fastest. var max = 10000000; var arr = new Array(max); for (let i = 0; i < max; i++) { arr[i] = true; } Which was ~ 85% faster than var max = 10000000; var arr = []; for (let i = 0; i < max; i++) { arr.push(true); } And indeed, the first snippet was much faster in my actual app as well

问题 Recently, I had to work on optimising a task that involved the creation of really large arrays (~ 10⁸ elements). I tested a few different methods, and, according to jsperf, the following option seemed to be the fastest. var max = 10000000; var arr = new Array(max); for (let i = 0; i < max; i++) { arr[i] = true; } Which was ~ 85% faster than var max = 10000000; var arr = []; for (let i = 0; i < max; i++) { arr.push(true); } And indeed, the first snippet was much faster in my actual app as well

问题 One answer is to create a new array that is one element shorter. Are there any other simpler ways to do this? 回答1: Here is one way to remove the first element of an array in vb.net. dim a(n) ... for i = 1 to ubound(a) a(i-1) = a(i) next i redim preserve a(ubound(a)-1) You could make a function for this to remove an arbitrary element of an array (Have a parameter for the initial value of the for loop). 回答2: You can use LINQ to produce your result in a very concise bit of code: Dim a2 = a.Skip

问题 Since arr is borrowed as mutable, the length of arr can't be gotten by calling len() . I'm stuck here, what's the right way to do it? fn double_last(arr: &mut[i32]) -> &i32 { let last = &mut arr[arr.len() - 1]; // borrow checker error. //let last = &mut arr[3]; // fine *last *= 2; last } fn main() { let mut a = [1,2,3,4]; println!("{}", double_last(&mut a)); println!("{:?}", a); } 回答1: This will hopefully be fixed with the introduction of non-lexical lifetimes and the accompanying changes

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 5 years ago . Improve this question I have an integer array: int a[5]={5,21,456,1,3} I need to store these number into char array so that the char array will have some thing like this: char *s="52145613"; Is there any library function in c for this? 回答1: sprintf do what you need. Little example

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 5 years ago . Improve this question I have an integer array: int a[5]={5,21,456,1,3} I need to store these number into char array so that the char array will have some thing like this: char *s="52145613"; Is there any library function in c for this? 回答1: sprintf do what you need. Little example