argv

I have a script that does various things and access paramenters using sys.argv but when the script gets to the unittest part of the code it says there is no module for this. The script that I have is: class MyScript(): def __init__(self): self.value = sys.argv[1] def hello(self): print self.value def suite(self): modules_to_test = ('external_sanity_onvif', 'starttest') alltests = unittest.TestSuite() for module in map(__import__, modules_to_test): alltests.addTest(unittest.findTestCases(module)) return alltests if __name__ == '__main__': Run = MyScript() Run.hello() log_file = 'log_file.txt'

I would like to parse a string like this: -o 1 --long "Some long string" into this: ["-o", "1", "--long", 'Some long string'] or similar. This is different than either getopt, or optparse, which start with sys.argv parsed input (like the output I have above). Is there a standard way to do this? Basically, this is "splitting" while keeping quoted strings together. My best function so far: import csv def split_quote(string,quotechar='"'): ''' >>> split_quote('--blah "Some argument" here') ['--blah', 'Some argument', 'here'] >>> split_quote("--blah 'Some argument' here", quotechar="'") ['--blah',

I am familiar with C, and have started experimenting in python. My question is regarding the sys.argv command. I've read it is used for a command line interpreter, but when trying to execute a simple program I don't get the results I expect. Code: import sys a = sys.argv[1] b = sys.argv[2] print a, b print a+b Input: python mySum.py 100 200 Output: 100 200 100200 When I add the two arguments they are concatenated instead of the two values being added together. It seems that the values are being taken as strings. How can I interpret them as numerics? You can convert the arguments to integers

So I'm wondering if command line parameters are always null terminated? Google seems to say yes, and compiling on GCC indicates this is the case, but can I guarantee this to always be true? int main(int argc, char** argv) { char *p; for(int cnt=1; cnt < argc; ++cnt) { p = argv[cnt]; printf("%d = [%s]\n", cnt, p); } return 0; } $ MyProgram -arg1 -arg2 -arg3 1 = -arg1 2 = -arg2 3 = -arg3 James McNellis Yes. The non-null pointers in the argv array point to C strings, which are by definition null terminated. The C Language Standard simply states that the array members "shall contain pointers to

In what encoding are the elements of sys.argv , in Python? are they encoded with the sys.getdefaultencoding() encoding? sys.getdefaultencoding(): Return the name of the current default string encoding used by the Unicode implementation. PS : As pointed out in some of the answers, sys.stdin.encoding would indeed be a better guess . I would love to see a definitive answer to this question, though, with pointers to solid sources! PPS : As Wim pointed out, Python 3 solves this issue by putting str objects in sys.argv (if I understand correctly). The question remains open for Python 2.x, though.

I am learning from code, and I am get confused by one of its lines which is: things = [float(arg) for arg in sys.argv[1:]] Omega_a, Omega_b, Delta_a, Delta_b, \ init_pop_a, init_pop_b, tstep, tfinal = things I have searched online and tried to understand what sys.arg means, and here is my understanding: So sys.argv[0] is the file name, and sys.argv[1:] is the rest of the parameters which should given by users. I am not sure am I understood it right, and if it is, then I don't understand why cant it be like: Omega_a = input() Omega_b = input() etc... What's the difference between these two ways

In a C program I can write argv[0] and the new name shows up in a ps listing. How can I do this in bash? You can do it when running a new program via exec -a <newname> . I've had a chance to go through the source for bash and it does not look like there is any support for writing to argv[0]. Just for the record, even though it does not exactly answer the original poster's question, this is something trivial to do with zsh : ARGV0=emacs nethack ( exec -a foo bash -c 'echo $0' ) I'm assuming you've got a shell script that you wish to execute such that the script process itself has a new argv[0]

CODE 1 #include<stdio.h> int main(int argc, char *argv[]) { int j; printf("%d", argv[1][0]); return 0; } CODE 2 #include<stdio.h> int main(int argc, char **argv) { int j; printf("%d", argv[1][0]); return 0; } CODE 1 and CODE 2 both give same output. but argument 2 of main function in CODE 1 and CODE 2 are different. Array of pointers are created above data section at compile time. argv is array of pointers. Then we should declare argument in main function as pointer to pointer to character i.e., **argv. How it is correct to declare as in CODE 1? Basically, char* argv[] means array of char