anova

How to perform single factor ANOVA in R with samples organized by column?

丶灬走出姿态 提交于 2019-11-29 14:03:54
I have a data set where the samples are grouped by column. The following sample dataset is similar to my data's format: a = c(1,3,4,6,8) b = c(3,6,8,3,6) c = c(2,1,4,3,6) d = c(2,2,3,3,4) mydata = data.frame(cbind(a,b,c,d)) When I perform a single factor ANOVA in Excel using the above dataset, I get the following results: I know a typical format in R is as follows: group measurement a 1 a 3 a 4 . . . . . . d 4 And the command to perform ANOVA in R would be to use aov(group~measurement, data = mydata) . How do I perform single factor ANOVA in R with samples organized by column rather than by

Setting Contrasts for ANOVA in R

蹲街弑〆低调 提交于 2019-11-29 12:52:50
I've been attempting to perform an ANOVA in R recently on the attached data frame. My question revolves around the setting of contrasts. My design is a 3x5 within-subjects design. There are 3 visual conditions under 'Circle1' and 5 audio under 'Beep1'. Does anyone have any idea how I should set the contrasts? This is something I'm unfamiliar with as I'm making the transition from point and click stats in SPSS to coded in R. Thanks for your time Data file: Nathaniel Payne Reiterating my answer from another stackoverflow question that was flagged as similar , since you didn't provide any code,

model.matrix(): why do I lose control of contrast in this case

谁说胖子不能爱 提交于 2019-11-29 12:46:31
Suppose we have a toy data frame: x <- data.frame(x1 = gl(3, 2, labels = letters[1:3]), x2 = gl(3, 2, labels = LETTERS[1:3])) I would like to construct a model matrix # x1b x1c x2B x2C # 1 0 0 0 0 # 2 0 0 0 0 # 3 1 0 1 0 # 4 1 0 1 0 # 5 0 1 0 1 # 6 0 1 0 1 by: model.matrix(~ x1 + x2 - 1, data = x, contrasts.arg = list(x1 = contr.treatment(letters[1:3]), x2 = contr.treatment(LETTERS[1:3]))) but actually I get: # x1a x1b x1c x2B x2C # 1 1 0 0 0 0 # 2 1 0 0 0 0 # 3 0 1 0 1 0 # 4 0 1 0 1 0 # 5 0 0 1 0 1 # 6 0 0 1 0 1 # attr(,"assign") # [1] 1 1 1 2 2 # attr(,"contrasts") # attr(,"contrasts")$x1 #

Repeated-measures / within-subjects ANOVA in R

匆匆过客 提交于 2019-11-28 16:52:36
问题 I'm attempting to run a repeated-meaures ANOVA using R. I've gone through various examples on various websites, but they never seem to talk about the error that I'm encountering. I assume I'm misunderstanding something important. The ANOVA I'm trying to run is on some data from an experiment using human participants. It has one DV and three IVs. All of the levels of all of the IVs are run on all participants, making it a three-way repeated-measures / within-subjects ANOVA. The code I'm

Fitting linear model / ANOVA by group [duplicate]

守給你的承諾、 提交于 2019-11-28 14:10:58
This question already has an answer here: Linear Regression and group by in R 10 answers I'm trying to run anova() in R and running into some difficulty. This is what I've done up to now to help shed some light on my question. Here is the str() of my data to this point. str(mhw) 'data.frame': 500 obs. of 5 variables: $ r : int 1 2 3 4 5 6 7 8 9 10 ... $ c : int 1 1 1 1 1 1 1 1 1 1 ... $ grain: num 3.63 4.07 4.51 3.9 3.63 3.16 3.18 3.42 3.97 3.4 ... $ straw: num 6.37 6.24 7.05 6.91 5.93 5.59 5.32 5.52 6.03 5.66 ... $ Quad : Factor w/ 4 levels "NE","NW","SE",..: 2 2 2 2 2 2 2 2 2 2 ... Column r

How to perform single factor ANOVA in R with samples organized by column?

。_饼干妹妹 提交于 2019-11-28 07:44:11
问题 I have a data set where the samples are grouped by column. The following sample dataset is similar to my data's format: a = c(1,3,4,6,8) b = c(3,6,8,3,6) c = c(2,1,4,3,6) d = c(2,2,3,3,4) mydata = data.frame(cbind(a,b,c,d)) When I perform a single factor ANOVA in Excel using the above dataset, I get the following results: I know a typical format in R is as follows: group measurement a 1 a 3 a 4 . . . . . . d 4 And the command to perform ANOVA in R would be to use aov(group~measurement, data =

Setting Contrasts for ANOVA in R

ぃ、小莉子 提交于 2019-11-28 06:32:32
问题 I've been attempting to perform an ANOVA in R recently on the attached data frame. My question revolves around the setting of contrasts. My design is a 3x5 within-subjects design. There are 3 visual conditions under 'Circle1' and 5 audio under 'Beep1'. Does anyone have any idea how I should set the contrasts? This is something I'm unfamiliar with as I'm making the transition from point and click stats in SPSS to coded in R. Thanks for your time Data file: 回答1: Reiterating my answer from

model.matrix(): why do I lose control of contrast in this case

你。 提交于 2019-11-28 05:59:07
问题 Suppose we have a toy data frame: x <- data.frame(x1 = gl(3, 2, labels = letters[1:3]), x2 = gl(3, 2, labels = LETTERS[1:3])) I would like to construct a model matrix # x1b x1c x2B x2C # 1 0 0 0 0 # 2 0 0 0 0 # 3 1 0 1 0 # 4 1 0 1 0 # 5 0 1 0 1 # 6 0 1 0 1 by: model.matrix(~ x1 + x2 - 1, data = x, contrasts.arg = list(x1 = contr.treatment(letters[1:3]), x2 = contr.treatment(LETTERS[1:3]))) but actually I get: # x1a x1b x1c x2B x2C # 1 1 0 0 0 0 # 2 1 0 0 0 0 # 3 0 1 0 1 0 # 4 0 1 0 1 0 # 5 0

R error which says “Models were not all fitted to the same size of dataset”

随声附和 提交于 2019-11-27 09:16:33
I have created two generalised linear models as follows: glm1 <-glm(Y ~ X1 + X2 + X3, family=binomial(link=logit)) glm2 <-glm(Y ~ X1 + X2, family=binomial(link=logit)) I then use the anova function: anova(glm2,glm1) but get an error message: "Error in anova.glmlist(c(list(object),dotargs), dispersion = dispersion, : models were not all fitted to the same size of dataset" What does this mean and how can I fix this? I have attach ed the dataset at the start of my code so both models are working off of the same dataset. The main cause of that error is when there are missing values in one or more

Extract p-value from aov

血红的双手。 提交于 2019-11-27 00:40:12
I am looking to extract the p-value generated from an anova in R. Here is what I am running: test <- aov(asq[,9] ~ asq[,187]) summary(test) Yields: Df Sum Sq Mean Sq F value Pr(>F) asq[, 187] 1 3.02 3.01951 12.333 0.0004599 *** Residuals 1335 326.85 0.24483 --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 12 observations deleted due to missingness When I look a the structure, this is what I see. I usually can work through lists to get what I need, but I am having a hard time with this one. A Google searched also seemed to reveal much simpler structures than I am getting. NOTE: