Does the C preprocessor remove instances of “&*”?
问题 I was playing around with gcc and tried the following bit of code: int A = 42; int *B = &A; int *C = &*B; And C == &A , as expected. But when I try: int *B = NULL; int *C = &*B; Turns out C == NULL , and no segfault. So &*B is not actually dereferencing B before taking its address. My guess is that the preprocessor is stripping out instances of &* and *& before they even get to the compiler since they negate each other, but I can't find any documentation to verify whether this is standard C