addition

How do I add two integers together with Twisted?

烂漫一生 提交于 2019-12-03 02:27:25
问题 I have two integers in my program; let's call them " a " and " b ". I would like to add them together and get another integer as a result. These are regular Python int objects. I'm wondering; how do I add them together with Twisted? Is there a special performAsynchronousAddition function somewhere? Do I need a Deferred ? What about the reactor? Is the reactor involved? 回答1: OK, to be clear. Twisted doesn't do anything about cpu bound tasks and for good reason. there's no way to make a compute

addition of one column with certain condition in another colum, like sumifs of excel

梦想与她 提交于 2019-12-02 19:29:23
问题 I have a matrix like this A=[ 1 2; 2 3; 3 4; 4 5; 5 6; 6 8; 7 9; 8 5; 9 4] Now I want to add a second column the condition is that if limit=0, and interval=3 and limit=limit+interval, or in other words, I have to sum column 2 when values of column 1, ranges like 0 to 3, 3 to 6, 6 to 9, and 9 to 12, and i want sum of corresponding values of column 2. my solution will be like that range- sum 0 to 3 9 3 to 6 19 6 to 9 18 like that I have a matrix of around 7000x2. In place of range just serial

Addition operator not working in JavaScript

徘徊边缘 提交于 2019-12-02 15:08:57
问题 Addition operator isn't working for me in Javascript. If I do 5+5, it gives me 55 instead of 10. How can I fix this? var numberOne = prompt (Enter first number.); if (numberOne > 0.00001) { var numberTwo = prompt(Enter the second number.); if (numberTwo > 0.00001) { var alertAnswer = alert (numberOne + numberTwo); } } 回答1: You're reading in strings, and concatenating them. You need to convert them to integers with parseInt . IE: var numberOne = parseInt(prompt("Enter first number."), 10); 回答2

How do I add two integers together with Twisted?

丶灬走出姿态 提交于 2019-12-02 14:22:10
I have two integers in my program; let's call them " a " and " b ". I would like to add them together and get another integer as a result. These are regular Python int objects. I'm wondering; how do I add them together with Twisted? Is there a special performAsynchronousAddition function somewhere? Do I need a Deferred ? What about the reactor? Is the reactor involved? OK, to be clear. Twisted doesn't do anything about cpu bound tasks and for good reason. there's no way to make a compute bound job go any quicker by reordering subtasks; the only thing you could possibly do is add more compute

addition of one column with certain condition in another colum, like sumifs of excel

半城伤御伤魂 提交于 2019-12-02 11:47:51
I have a matrix like this A=[ 1 2; 2 3; 3 4; 4 5; 5 6; 6 8; 7 9; 8 5; 9 4] Now I want to add a second column the condition is that if limit=0, and interval=3 and limit=limit+interval, or in other words, I have to sum column 2 when values of column 1, ranges like 0 to 3, 3 to 6, 6 to 9, and 9 to 12, and i want sum of corresponding values of column 2. my solution will be like that range- sum 0 to 3 9 3 to 6 19 6 to 9 18 like that I have a matrix of around 7000x2. In place of range just serial no may also be given. This is just an example. This is a job for ACCUMARRAY . First, you construct an

Add 2 numbers and print the result using Assembly x86

柔情痞子 提交于 2019-12-02 11:22:14
I'm a novice Assembly x86 Learner, and i want to add two numbers (5+5) and print the result on the screen. here is my code: global _start section .text _start: mov eax, 5 mov ebx, 5 add eax, ebx push eax mov eax, 4 ; call the write syscall mov ebx, 1 ; STDOUT pop ecx ; Result mov edx, 0x1 int 0x80 ; Exit mov eax, 0x1 xor ebx, ebx int 0x80 Correct me please Another approach to convert an unsigned integer to a string and write it: section .text global _start _start: mov eax, 1234567890 mov ebx, 5 add eax, ebx ; Convert EAX to ASCII and store it onto the stack sub esp, 16 ; reserve space on the

How to perform addition in text file bypassing strings

白昼怎懂夜的黑 提交于 2019-12-02 10:17:15
I converted my csv file to text file and I want to add the numbers inside the text file. When I run my code get an error. Assuming the error code I want to write logic that would bypass my strings and just add the numeric values. `import csv csv_file = 'Annual Budget.csv' txt_file = 'annual_budget.txt' with open(txt_file, 'w') as my_output_file: with open(csv_file, 'r') as my_input_file: reader = csv.reader(my_input_file) for row in reader: my_output_file.write(" ".join(row)+'\n') data = [] with open(r'annual_budget.txt') as f: for line in f: fields = line.split() rowdata = map(float, fields)

How to add elements individually in tuple?

北城以北 提交于 2019-12-02 07:25:41
问题 How to add elements individually within the tuple? For example, i need (2, 4) from (0,1) + (2,3) , I've been doing it as such but is there a more pythonic / less verbose way to do the same? >>> x = (0,1) >>> y = (2,3) >>> x + y (0, 1, 2, 3) >>> tuple(i+j for i,j in zip(x,y)) (2, 4) 回答1: You can use zip and sum here: Example: >>> x = (0, 1) >>> y = (2, 3) >>> tuple(map(sum, zip(x, y))) (2, 4) zip lets us combine elements of two iterables or lists in pairs. sum lets us sum the pairs map lets us

How to add elements individually in tuple?

蓝咒 提交于 2019-12-02 07:24:17
How to add elements individually within the tuple? For example, i need (2, 4) from (0,1) + (2,3) , I've been doing it as such but is there a more pythonic / less verbose way to do the same? >>> x = (0,1) >>> y = (2,3) >>> x + y (0, 1, 2, 3) >>> tuple(i+j for i,j in zip(x,y)) (2, 4) James Mills You can use zip and sum here: Example: >>> x = (0, 1) >>> y = (2, 3) >>> tuple(map(sum, zip(x, y))) (2, 4) zip lets us combine elements of two iterables or lists in pairs. sum lets us sum the pairs map lets us apply the sum function per pair. finally we convert the resulting list ( or iterable in Python

C program not adding float correctly

荒凉一梦 提交于 2019-12-02 07:11:09
问题 I have a method that looks like this: float * mutate(float* organism){ int i; float sign = 1; static float newOrg[INPUTS] = {0}; for (i = 0;i<INPUTS;i++){ if (rand() % 2 == 0) { sign = 1; } else { sign = -1; } float temp = (organism[i] + sign); printf("bf: %f af: %f diff: %f sign: %f sign2: %f temp: %f\n\n", organism[i], (organism[i] + sign), (organism[i] + sign)-organism[i], sign, sign+sign, temp); newOrg[i] = organism[i] + sign; } return newOrg; } When sign is not 0 the first two "%f" s are