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问题 Given a pandas.DataFrame with a column holding mixed datatypes, like e.g. df = pd.DataFrame({'mixed': [pd.Timestamp('2020-10-04'), 999, 'a string']}) I was wondering how to obtain the datatypes of the individual objects in the column (Series)? Suppose I want to modify all entries in the Series that are of a certain type, like multiply all integers by some factor. I could iteratively derive a mask and use it in loc , like m = np.array([isinstance(v, int) for v in df['mixed']]) df.loc[m, 'mixed

问题 Given a pandas.DataFrame with a column holding mixed datatypes, like e.g. df = pd.DataFrame({'mixed': [pd.Timestamp('2020-10-04'), 999, 'a string']}) I was wondering how to obtain the datatypes of the individual objects in the column (Series)? Suppose I want to modify all entries in the Series that are of a certain type, like multiply all integers by some factor. I could iteratively derive a mask and use it in loc , like m = np.array([isinstance(v, int) for v in df['mixed']]) df.loc[m, 'mixed

问题 Given a pandas.DataFrame with a column holding mixed datatypes, like e.g. df = pd.DataFrame({'mixed': [pd.Timestamp('2020-10-04'), 999, 'a string']}) I was wondering how to obtain the datatypes of the individual objects in the column (Series)? Suppose I want to modify all entries in the Series that are of a certain type, like multiply all integers by some factor. I could iteratively derive a mask and use it in loc , like m = np.array([isinstance(v, int) for v in df['mixed']]) df.loc[m, 'mixed

问题 Given a handle of a window, how can I close the window by using the window handle? 回答1: The easiest way is to use PInvoke and do a SendMessage with WM_CLOSE . [DllImport("user32.dll", CharSet = CharSet.Auto)] private static extern IntPtr SendMessage(IntPtr hWnd, UInt32 Msg, IntPtr wParam, IntPtr lParam); private const UInt32 WM_CLOSE = 0x0010; void CloseWindow(IntPtr hwnd) { SendMessage(hwnd, WM_CLOSE, IntPtr.Zero, IntPtr.Zero); } 回答2: Not sure if there is another way but you could PInvoke

问题 I'm using Infinispan with 6.0.2 with Hibernate Search 4.4.0. In the begining, after I execute a query like CacheQuery cq = SearchManager.getQuery(query,Hibernate.class).projection("id"); I use the cq.list() to get "id". But now the number of results reaches 300.000, because of the designing fo DB(cant change), the duplicate id is almost 29,000. I wrote this to get "id": for(int i=0;i<listObject.size();i++) { Object[] rdf = (Object[])listObject.get(i); if(!result.contains((String) rdf[0]))

问题 I'm trying to use the rolling() function on a pandas data frame with monthly data. However, I dropped some NaN values, so now there are some gaps in my time series. Therefore, the basic window parameter gives a misleading answer since it just looks at the previous observation: import pandas as pd import numpy as np import random dft = pd.DataFrame(np.random.randint(0,10,size=len(dt)),index=dt) dft.columns = ['value'] dft['value'] = np.where(dft['value'] < 3,np.nan,dft['value']) dft = dft

问题 I need to reorder a sorted list so the "middle" element is the highest number. The numbers leading up to the middle are incremental, the numbers past the middle are in decreasing order. I have the following working solution, but have a feeling that it can be done simpler: foo = range(7) bar = [n for i, n in enumerate(foo) if n % 2 == len(foo) % 2] bar += [n for n in reversed(foo) if n not in bar] bar [1, 3, 5, 6, 4, 2, 0] 回答1: how about: foo[len(foo)%2::2] + foo[::-2] In [1]: foo = range(7)

问题 I'm trying to make my own Tabs component, so that I can use tabs in my app. However I seem to be having issues trying to extract the child components I need by type. import React from 'react' export class Tabs extends React.Component { render() { let children = this.props.children let tablinks = React.Children.map(children, x => { console.log(x.type.displayName) // Always undefined if (x.type.displayName == 'Tab Link') { return x } }) return ( <div className="tabs"></div> ) } } export class

问题 I have a problem with my code, even though it hasn't been modified in any way. It just suddenly threw this message. As you can see on the left, that they are all in the correct package, and have correct names. What can I do to fix this problem? 回答1: Clear the cache to fix it. In Windows, cache is located at: C:\Users\username\AppData\Local\NetBeans\... On Linux, cache is at: /home/username/.cache/netbeans/... After clearing the cache restart netbeans. 回答2: If clearing the cache still doesn't

问题 I need to reorder a sorted list so the "middle" element is the highest number. The numbers leading up to the middle are incremental, the numbers past the middle are in decreasing order. I have the following working solution, but have a feeling that it can be done simpler: foo = range(7) bar = [n for i, n in enumerate(foo) if n % 2 == len(foo) % 2] bar += [n for n in reversed(foo) if n not in bar] bar [1, 3, 5, 6, 4, 2, 0] 回答1: how about: foo[len(foo)%2::2] + foo[::-2] In [1]: foo = range(7)