We have now started using calc()
in css, for setting widths on a result of calculation. For example:
<div id='parent'> <div id='calcWidth'></div> </div> #parent{ width:100px; } #calcWidth{ width:calc(100% - 3px); height:100px; background:red; }
I know how calc()
works, but I just want to know what is returned in css, in the place of calc(100% - 3px);
in the example given above.
Whats my confusion?
In the above example
width:calc(100% - 3px);
say the
100%
width is actually100px
, which will be determined at runtime by css.So the calculated width will be
100px-3px=97px
97px and if you convert it to%
97%
right?
But now, there are two possibilities
97px
is returned, which is set as a width.97%
is returned, which is set as a width.
My Question is:
In both cases now the width shall be set to
97px
, but what is returned as a result ofwidth:calc(100% - 3px);
,97px
OR97%
?
you can also see this fiddle: http://jsfiddle.net/8yspnuuw/1/
EDIT: please read
See friends: Take a simple example:
<div class='parent'> <div class='child'> </div> </div> .parent{ width:200px; } .child{ width:20% }
I know the width of child will become 160 px when it is rendered. okay! but thats not what is set in css right? css sets it in %, it is just rendered in pixels.
So similarly, using calc, does it return %
or pixel
Or to explain my question, read BoltClocks answer, what is the computed value, (and not the used value, i know that is in pixels)