PHP Warning: mysql_query() expects parameter 1 to be string [duplicate]

问题:

Possible Duplicate:
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select

Hopefully a quick one for one of you out there.

I'm getting two errors that are related to :

Warning: mysql_query() expects parameter 1 to be string, array given

My code is as follows...

pageSelector; return $pagenum; } $perpage=3; $now=time()-(1 * 24 * 60 * 60); $sql="SELECT count(*) AS total FROM event_tbl WHERE dates>'$now'"; $sql=mysql_query($sql); $pagenum=pageselector ($pagenum, $sql['total'], '', $perpage); $eventlist=array(); $sql="SELECT * FROM event_tbl WHERE dates>'$now' ORDER BY dates ASC"; $sql=mysql_query($sql); $sql=mysql_fetch_array($sql); while ($sqlevent=mysql_query($sql)){ $eventlist[]=$sqlevent['id']; } for ($i=0; $i'; $smallevent['description']=strip_tags($smallevent['description'], ''); $shortdescription=substr($smallevent['description'], 0, 350); print ''.$smallevent['name'].' - Date: '.date('j/n/Y', $smallevent['dates']).' - Price:
'; else print 'SOLD OUT
'; print '
'; print $shortdescription.'...'; print '

'; print ' '; print '

'; } ?>

The two error lines are :

while ($sqlevent=mysql_query($sql)){   $eventlist[]=$sqlevent['id'];   }  $smallevent=mysql_query($sql); 

I've got a DB Connect file (Although not sure whether its triggering or not??)

Any help appreciated.

Cheers

回答1:

$eventlist=array(); $sql="SELECT * FROM event_tbl WHERE dates>'$now' ORDER BY dates ASC"; $sql=mysql_query($sql); $sql=mysql_fetch_array($sql); while ($sqlevent=mysql_query($sql)){   $eventlist[]=$sqlevent['id']; } 

The error is pretty clear. For some reason (I don't know what), you call mysql_query again with an array.

Perhaps you meant:

$eventlist=array(); $sql = "SELECT * FROM event_tbl WHERE dates > '$now' ORDER BY dates ASC"; $res = mysql_query($sql); while ($sqlevent = mysql_fetch_array($res)) {   $eventlist[] = $sqlevent['id']; } 

回答2:

You have to use different names for your variables. Just before the faulty while :

$sql=mysql_query($sql); $sql=mysql_fetch_array($sql); 

The second line assigns the result of mysql_fetch_array to the variable named $sql which is then no longer a string. You can use $sql_result for example.

However, reading your code, I think there's other mistakes. For example, I think you want to do something like this :

$result = mysql_query($sql); while ($row = mysql_fetch_array($result)){   $eventlist[] = $row['id']; } 

mysql_query is for getting the results from the query and then you can read the results with mysql_fetch_array. You can't use the result of mysql_query directly. There's plenty of good examples in the linked documentation, you should read them.

The second problem is exactly of the same kind.

回答3:

$sql=mysql_fetch_array($sql);   while ($sqlevent=mysql_query($sql)){ $eventlist[]=$sqlevent['id']; } 

$sql is an array as mysql_fetch_array returns an array !!! try using other variable !

---

$eventlist=array(); $sql="SELECT * FROM event_tbl WHERE dates>'$now' ORDER BY dates ASC"; $result=mysql_query($sql,$connection); $sql=mysql_fetch_array($result); 

....

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