I have url that returns date in this format
url_date = "2015-01-12T08:43:02Z"
I don't know why there are strings, it would have been simpler to get it as "2015-01-1208:43:02"
which would have been simpler to parse using
datetime.datetime.strptime(url_date , '%Y-%m-%d')
but it does not work. I have tried with
%Y-%m-%d
%Y-%m-%d-%H-%M-%S
%Y-%m-%d-%H-%M-%S-%Z
But I keep getting errors like "time data 2015-01-12T08:43:02Z does not match ..."
The format you are looking for is - '%Y-%m-%dT%H:%M:%SZ'
.
Example -
>>> url_date = "2015-01-12T08:43:02Z"
>>> import datetime
>>> datetime.datetime.strptime(url_date , '%Y-%m-%dT%H:%M:%SZ')
datetime.datetime(2015, 1, 12, 8, 43, 2)
For the new requirement in comments -
if I wanted to get a time back with the strings as in 2015-01-12:08:43:02 which methods should after datetime().datetime()
You would need to use .strftime()
on the datetime.datetime
object with the format - '%Y-%m-%d:%H:%M:%S'
. Example -
>>> url_date = "2015-01-12T08:43:02Z"
>>> dt = datetime.datetime.strptime(url_date , '%Y-%m-%dT%H:%M:%SZ')
>>> dt.strftime('%Y-%m-%d:%H:%M:%S')
'2015-01-12:08:43:02'
If you wanted the time component , you can use .time()
for that. Example -
>>> dt = datetime.datetime.strptime(url_date , '%Y-%m-%dT%H:%M:%SZ')
>>> dt.time()
datetime.time(8, 43, 2)
You were getting close with the "Z" in your final attempt - you need to specify the T, Z, and colon literal values in your format string.
>>> import datetime
>>> url_date = "2015-01-12T08:43:02Z"
>>> datetime.datetime.strptime(url_date , '%Y-%m-%dT%H:%M:%SZ')
datetime.datetime(2015, 1, 12, 8, 43, 2)
来源:https://stackoverflow.com/questions/33397107/python-parsing-date-with-strptime