I get a file path as an input to mule inside xml. Using XPATH expression, I am able to extract the path. I want to read a particular file from that path. I tried to define file inbound endpoint as below. But it doesn't seem to be working.
<flow name="flow1">
....
....
<set-session-variable variableName="filePath" value="#[xpath://filePath]" />
<flow-ref name="fileFlow"/>
</flow>
<flow name="fileFlow">
<file:inbound-endpoint path="#[header:SESSION:filePath]" />
</flow>
My understanding here is that no code can be placed before an inbound-endpoint. Hence I defined it in another flow. Please suggest if there is a way to read the file from a specified path.
Unfortunately, you cannot programmatically call an inbound-endpoint like that.
However the same functionality can be achieved using the Mule requester module:
Example:
<flow name="RequestFile" doc:name="RequestFile">
<http:inbound-endpoint exchange-pattern="request-response" host="localhost" port="8081" path="requestfile" doc:name="HTTP"/>
<mulerequester:request config-ref="Mule_Requester" resource="file:///s/tmp/demorequester/read/#[message.inboundProperties['filename']]" returnClass="java.lang.String" doc:name="Request a file"/>
</flow>
Instructions here: https://github.com/mulesoft/mule-module-requester and https://blogs.mulesoft.com/dev/mule-dev/introducing-the-mule-requester-module/
来源:https://stackoverflow.com/questions/21636573/unable-to-create-dynamic-file-inbound-endpoint-in-mule