问题
How can a Java Date
be converted into a double
that represents a Julian day?
How can a Julian day number be converted into a Java Date
?
public static double dateToJulian(Date date) {
GregorianCalendar calendar = new GregorianCalendar();
calendar.setTime(date);
int year;
int month;
float day;
int a;
int b;
double d;
double frac;
frac = (calendar.get(Calendar.HOUR_OF_DAY) / 0.000024 + calendar.get(Calendar.MINUTE) / 0.001440);
b = 0;
year = calendar.get(Calendar.YEAR);
month = calendar.get(Calendar.MONTH) + 1;
DecimalFormat ceroPlaces = new DecimalFormat("0");
day = calendar.get(Calendar.DAY_OF_MONTH);
day = Float.parseFloat(ceroPlaces.format(day) + "." + ceroPlaces.format(Math.round(frac)));
if (month < 3) {
year--;
month += 12;
}
if (FuncionSoporte.compararFechas(calendar.getTime(), calendar.getGregorianChange()) > 0) {
a = year / 100;
b = 2 - a + a / 4;
}
d = Math.floor(365.25 * year) + Math.floor(30.6001 * (month + 1)) + day + 1720994.5 + b;
return (d);
}
public static Date julianToDate(double jd) {
double z, f, a, b, c, d, e, m, aux;
Date date = new Date();
jd += 0.5;
z = Math.floor(jd);
f = jd - z;
if (z >= 2299161.0) {
a = Math.floor((z - 1867216.25) / 36524.25);
a = z + 1 + a - Math.floor(a / 4);
} else {
a = z;
}
b = a + 1524;
c = Math.floor((b - 122.1) / 365.25);
d = Math.floor(365.25 * c);
e = Math.floor((b - d) / 30.6001);
aux = b - d - Math.floor(30.6001 * e) + f;
Calendar calendar = new GregorianCalendar();
calendar.setTime(date);
calendar.set(Calendar.DAY_OF_MONTH, (int) aux);
aux = ((aux - calendar.get(Calendar.DAY_OF_MONTH)) * 24);
calendar.set(Calendar.HOUR_OF_DAY, (int) aux);
calendar.set(Calendar.MINUTE, (int) ((aux - calendar.get(Calendar.HOUR_OF_DAY)) * 60));
if (e < 13.5) {
m = e - 1;
} else {
m = e - 13;
}
// Se le resta uno al mes por el manejo de JAVA, donde los meses empiezan en 0.
calendar.set(Calendar.MONTH, (int) m - 1);
if (m > 2.5) {
calendar.set(Calendar.YEAR, (int) (c - 4716));
} else {
calendar.set(Calendar.YEAR, (int) (c - 4715));
}
return calendar.getTime();
}
EDIT: Added FuncionSoporte.java code.
public class FuncionSoporte {
/**
* Compare 2 dates. If the first is after the second result will be positive, if the second is after then negative, 0 if they are equal.
*/
public static int compararFechas(Date d1, Date d2) {
Calendar c1 = new GregorianCalendar();
c1.setTime(d1);
Calendar c2 = new GregorianCalendar();
c2.setTime(d2);
if (c1.get(Calendar.YEAR) == c2.get(Calendar.YEAR)) {
if (c1.get(Calendar.MONTH) == c2.get(Calendar.MONTH)) {
return c1.get(Calendar.DAY_OF_MONTH) - c2.get(Calendar.DAY_OF_MONTH);
} else {
return c1.get(Calendar.MONTH) - c2.get(Calendar.MONTH);
}
} else {
return c1.get(Calendar.YEAR) - c2.get(Calendar.YEAR);
}
}
}
来源:https://stackoverflow.com/questions/5655034/how-can-i-convert-between-a-java-date-and-julian-day-number