I am working on an image slideshow, and the fadeOut()
functionality working with every image change, but the next image appears abruptly. I want it to fade in. I can't seem to get it working.
Here is the code without any fadeIn()
:
HTML:
<div id="backgroundChanger">
<img class="active" src="background1.jpg"/>
<img src="background2.jpg"/>
<img src="background3.jpg"/>
CSS:
#backgroundChanger{
position:relative;
}
#backgroundChanger img{
position:absolute;
z-index:-3
}
#backgroundChanger img.active{
z-index:-1;
}
Javascript:
function cycleImages(){
var $active = $('#backgroundChanger .active');
var $next = ($active.next().length > 0) ? $active.next() : $('#backgroundChanger img:first');
$next.css('z-index',-2);
$active.fadeOut(1500,function(){
$active.css('z-index',-3).show().removeClass('active');
$next.css('z-index',-1).addClass('active');
});
}
$(document).ready(function(){
setInterval('cycleImages()', 7000);
})
I'd recommend something like this for your interval function:
window.setInterval(function (){
var images = $('#backgroundChanger img');
var active, next;
images.each(function(index, img) {
if($(img).hasClass('active')) {
active = index;
next = (index === images.length - 1) ? 0 : index + 1;
}
});
$(images[active]).fadeOut(1000, function() {
$(images[next]).fadeIn(1000);
});
$(images[next]).addClass('active');
$(images[active]).removeClass('active');
}, 3000);
And this is all you'd need for your css:
#backgroundChanger img:first-child {
display: block;
}
#backgroundChanger img {
display: none;
}
And keep the same HTML and you should be good to go!
You can fadeIn()
the next image in the callback of fadeOut()
as shown below:
$(window).load(function() {
var $slider = $("#backgroundChanger"),
$slides = $slider.find("img"),
$firstSlide = $slides.first();
function cycleImages() {
var $active = $('#backgroundChanger .active'),
$next = ($active.next().length > 0) ? $active.next() : $firstSlide;
$active.fadeOut(1000, function() {
$active.removeClass('active');
$next.fadeIn(1000).addClass('active');
});
}
setInterval(cycleImages, 3000);
})
#backgroundChanger img {
position: absolute;
width: 150px;
height: 100px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="backgroundChanger">
<img class="active" src="http://i46.tinypic.com/2epim8j.jpg" />
<img src="http://i49.tinypic.com/28vepvr.jpg" />
<img src="http://i50.tinypic.com/f0ud01.jpg" />
</div>
Notes:
- Since we're dealing with images, It's better to use
load()
handler thanready()
to make sure the slide show starts after the images are loaded - You can slightly improve the performance by caching the elements accessed frequently
- You don't have to play with
z-index
property at all since bothfadeIn()
andfadeOut()
changes the elements `display property itself
来源:https://stackoverflow.com/questions/22430281/fadein-images-in-slideshow-using-jquery