问题
I have a struct definition with about 25 elements
struct X { field 1; field 2; .. };
and I\'m trying to fill it with some map values
Map<String,String> A
and it appears to be very annoying to do such thing n times
X->xx = A[\"aaa\"]
every time that I want to fill my message struct.
Is it possible to access the members by name, e.g.
X->get_instance_of(\"xx\").set(A[\"aaa\"]);
and put it into a loop?
回答1:
C++ lacks built-in reflection capabilities of more dynamic languages, so you cannot do what you would like using he out of the box capabilities of the language.
However, if all members are of the same type, you can do it with a map of pointers to members and a little preparation:
// typedef for the pointer-to-member
typedef int X::*ptr_attr;
// Declare the map of pointers to members
map<string,ptr_attr> mattr;
// Add pointers to individual members one by one:
mattr["xx"] = &X::xx;
mattr["yy"] = &X::yy;
// Now that you have an instance of x...
X x;
// you can access its members by pointers using the syntax below:
x.*mattr["xx"] = A["aa"];
回答2:
Short answer: no. This is C++, a statically compiled language, where the structure member names are converted by the compiler into memory offsets. It is not dynamic like PHP or Python where the runtime is involved with all variable references.
回答3:
No. C++ doesn't have reflection. Java does though. Unsurprisingly, SOA related stuff is more probably encountered with languages like Java than it is with languages like C.
回答4:
It's not really possible to do that; the information you need is no longer present at runtime. You might be able to do something with a map and some pointers, but to be honest you would probably be better off just wrapping it up in a function that takes a map and puts the values into the appropriate fields.
回答5:
You could create a wrapper objet for your struct with set/get accessors that will let you iterate over string values for filling/reading the underlying struct that is static.
来源：https://stackoverflow.com/questions/9468719/get-attribute-by-name