问题
I am asking this basic question to make the records straight. Have referred this question and its currently accepted answer, which is not convincing. However the second most voted answer gives better insight, but not perfect either.
While reading below, distinguish between the inline
keyword and “inlining” concept.
Here is my take:
The inlining concept
This is done to save the call overhead of a function. It\'s more similar to macro-style code replacement. Nothing to be disputed.
The inline
keyword
Perception A
The
inline
keyword is a request to the compiler usually used for smaller functions, so that compiler can optimize it and make faster calls. The Compiler is free to ignore it.
I dispute this, for below reasons:
- Larger and recursive functions are not inlined and the compiler ignores the
inline
keyword. - Smaller functions are automatically inlined by the optimizer irrespective of the
inline
keyword being mentioned or not.
It\'s quite clear that the user doesn\'t have any control over function inlining with the use of keyword inline
.
Perception B
inline
has nothing to do with the concept of inlining. Puttinginline
ahead of big / recursive function won\'t help and smaller function won\'t need it, for being inlined.The only deterministic use of
inline
is to maintain the One Definition Rule.
i.e. if a function is declared with inline
then only below things are mandated:
- Even if its body is found in multiple translation units (e.g. include that header in multiple
.cpp
files), the compiler will generate only 1 definition and avoid multiple symbol linker error. (Note: If the bodies of that function are different then it is undefined behavior.) - The body of the
inline
function has to be visible / accessible in all the translation units who use it. In other words, declaring aninline
function in.h
and defining in any one.cpp
file will result in an “undefined symbol linker error” for other.cpp
files
Verdict
The “A” perception is entirely wrong and the “B” perception is entirely right.
There are some quotes in standard on this, however I am expecting an answer which logically explains if this verdict is true or false.
回答1:
I wasn't sure about your claim:
Smaller functions are automatically "inlined" by optimizer irrespective of inline is mentioned or not... It's quite clear that the user doesn't have any control over function "inlining" with the use of keyword
inline
.
I've heard that compilers are free to ignore your inline
request, but I didn't think they disregarded it completely.
I looked through the Github repository for Clang and LLVM to find out. (Thanks, open source software!) I found out that The inline
keyword does make Clang/LLVM more likely to inline a function.
The Search
Searching for the word inline
in the Clang repository leads to the token specifier kw_inline
. It looks like Clang uses a clever macro-based system to build the lexer and other keyword-related functions, so there's noting direct like if (tokenString == "inline") return kw_inline
to be found. But Here in ParseDecl.cpp, we see that kw_inline
results in a call to DeclSpec::setFunctionSpecInline()
.
case tok::kw_inline:
isInvalid = DS.setFunctionSpecInline(Loc, PrevSpec, DiagID);
break;
Inside that function, we set a bit and emit a warning if it's a duplicate inline
:
if (FS_inline_specified) {
DiagID = diag::warn_duplicate_declspec;
PrevSpec = "inline";
return true;
}
FS_inline_specified = true;
FS_inlineLoc = Loc;
return false;
Searching for FS_inline_specified
elsewhere, we see it's a single bit in a bitfield, and it's used in a getter function, isInlineSpecified()
:
bool isInlineSpecified() const {
return FS_inline_specified | FS_forceinline_specified;
}
Searching for call sites of isInlineSpecified()
, we find the codegen, where we convert the C++ parse tree into LLVM intermediate representation:
if (!CGM.getCodeGenOpts().NoInline) {
for (auto RI : FD->redecls())
if (RI->isInlineSpecified()) {
Fn->addFnAttr(llvm::Attribute::InlineHint);
break;
}
} else if (!FD->hasAttr<AlwaysInlineAttr>())
Fn->addFnAttr(llvm::Attribute::NoInline);
Clang to LLVM
We are done with the C++ parsing stage. Now our inline
specifier is converted to an attribute of the language-neutral LLVM Function
object. We switch from Clang to the LLVM repository.
Searching for llvm::Attribute::InlineHint
yields the method Inliner::getInlineThreshold(CallSite CS)
(with a scary-looking braceless if
block):
// Listen to the inlinehint attribute when it would increase the threshold
// and the caller does not need to minimize its size.
Function *Callee = CS.getCalledFunction();
bool InlineHint = Callee && !Callee->isDeclaration() &&
Callee->getAttributes().hasAttribute(AttributeSet::FunctionIndex,
Attribute::InlineHint);
if (InlineHint && HintThreshold > thres
&& !Caller->getAttributes().hasAttribute(AttributeSet::FunctionIndex,
Attribute::MinSize))
thres = HintThreshold;
So we already have a baseline inlining threshold from the optimization level and other factors, but if it's lower than the global HintThreshold
, we bump it up. (HintThreshold is settable from the command line.)
getInlineThreshold()
appears to have only one call site, a member of SimpleInliner
:
InlineCost getInlineCost(CallSite CS) override {
return ICA->getInlineCost(CS, getInlineThreshold(CS));
}
It calls a virtual method, also named getInlineCost
, on its member pointer to an instance of InlineCostAnalysis
.
Searching for ::getInlineCost()
to find the versions that are class members, we find one that's a member of AlwaysInline
- which is a non-standard but widely supported compiler feature - and another that's a member of InlineCostAnalysis
. It uses its Threshold
parameter here:
CallAnalyzer CA(Callee->getDataLayout(), *TTI, AT, *Callee, Threshold);
bool ShouldInline = CA.analyzeCall(CS);
CallAnalyzer::analyzeCall()
is over 200 lines and does the real nitty gritty work of deciding if the function is inlineable. It weighs many factors, but as we read through the method we see that all its computations either manipulate the Threshold
or the Cost
. And at the end:
return Cost < Threshold;
But the return value named ShouldInline
is really a misnomer. In fact the main purpose of analyzeCall()
is to set the Cost
and Threshold
member variables on the CallAnalyzer
object. The return value only indicates the case when some other factor has overridden the cost-vs-threshold analysis, as we see here:
// Check if there was a reason to force inlining or no inlining.
if (!ShouldInline && CA.getCost() < CA.getThreshold())
return InlineCost::getNever();
if (ShouldInline && CA.getCost() >= CA.getThreshold())
return InlineCost::getAlways();
Otherwise, we return an object that stores the Cost
and Threshold
.
return llvm::InlineCost::get(CA.getCost(), CA.getThreshold());
So we're not returning a yes-or-no decision in most cases. The search continues! Where is this return value of getInlineCost()
used?
The Real Decision
It's found in bool Inliner::shouldInline(CallSite CS)
. Another big function. It calls getInlineCost()
right at the beginning.
It turns out that getInlineCost
analyzes the intrinsic cost of inlining the function - its argument signature, code length, recursion, branching, linkage, etc. - and some aggregate information about every place the function is used. On the other hand, shouldInline()
combines this information with more data about a specific place where the function is used.
Throughout the method there are calls to InlineCost::costDelta()
- which will use the InlineCost
s Threshold
value as computed by analyzeCall()
. Finally, we return a bool
. The decision is made. In Inliner::runOnSCC()
:
if (!shouldInline(CS)) {
emitOptimizationRemarkMissed(CallerCtx, DEBUG_TYPE, *Caller, DLoc,
Twine(Callee->getName() +
" will not be inlined into " +
Caller->getName()));
continue;
}
// Attempt to inline the function.
if (!InlineCallIfPossible(CS, InlineInfo, InlinedArrayAllocas,
InlineHistoryID, InsertLifetime, DL)) {
emitOptimizationRemarkMissed(CallerCtx, DEBUG_TYPE, *Caller, DLoc,
Twine(Callee->getName() +
" will not be inlined into " +
Caller->getName()));
continue;
}
++NumInlined;
InlineCallIfPossible()
does the inlining based on shouldInline()
's decision.
So the Threshold
was affected by the inline
keyword, and is used in the end to decide whether to inline.
Therefore, your Perception B is partly wrong because at least one major compiler changes its optimization behavior based on the inline
keyword.
However, we can also see that inline
is only a hint, and other factors may outweigh it.
回答2:
Both are correct.
The use of inline
might, or might not, influence the compiler's decision to inline any particular call to the function. So A is correct - it acts as a non-binding request that calls to the function be inlined, which the compiler is free to ignore.
The semantic effect of inline
is to relax the restrictions of the One Definition Rule to allow identical definitions in multiple translation units, as described in B. For many compilers, this is necessary to allow the inlining of function calls - the definition must be available at that point, and compilers are only required to process one translation unit at a time.
来源:https://stackoverflow.com/questions/27042935/inline-keyword-vs-inlining-concept