Transformed DStream in pyspark gives error when pprint called on it

问题

I'm exploring Spark Streaming through PySpark, and hitting an error when I try to use the transform function with take.

I can successfully use sortBy against the DStream via transform and pprint the result.

author_counts_sorted_dstream = author_counts_dstream.transform\
  (lambda foo:foo\
   .sortBy(lambda x:x[0].lower())\
   .sortBy(lambda x:x[1],ascending=False))
author_counts_sorted_dstream.pprint()

But if I use take following the same pattern and try to pprint it:

top_five = author_counts_sorted_dstream.transform\
  (lambda rdd:rdd.take(5))
top_five.pprint()

the job fails with

Py4JJavaError: An error occurred while calling o25.awaitTermination.
: org.apache.spark.SparkException: An exception was raised by Python:
Traceback (most recent call last):
  File "/usr/local/spark/python/pyspark/streaming/util.py", line 67, in call
    return r._jrdd
AttributeError: 'list' object has no attribute '_jrdd'

You can see the full code and output in the notebook here.

What am I doing wrong?

回答1:

Function you pass to transform should transform from RDD to RDD. If you use an action, like take, you have to convert the result back to RDD:

sc: SparkContext = ...

author_counts_sorted_dstream.transform(
  lambda rdd: sc.parallelize(rdd.take(5))
)

In contrast RDD.sortBy used is a transformation (returns an RDD) so there is no need for further parallelization.

On a side note following function:

lambda foo: foo \
    .sortBy(lambda x:x[0].lower()) \
    .sortBy(lambda x:x[1], ascending=False)

doesn't make much sense. Remember that Spark sort by shuffle therefore it is not stable. If you want to sort by multiple fields you should use a composite key like:

lambda x: (x[0].lower(), -x[1])

来源：https://stackoverflow.com/questions/41483746/transformed-dstream-in-pyspark-gives-error-when-pprint-called-on-it