I have the following code, which writes 6 floats to disk in binary form and reads them back:
#include <iostream>
#include <cstdio>
int main()
{
int numSegs = 2;
int numVars = 3;
float * data = new float[numSegs * numVars];
for (int i = 0; i < numVars * numSegs; ++i) {
data[i] = i * .23;
std::cout << data[i] << std::endl;
}
FILE * handle = std::fopen("./sandbox.out", "wb");
long elementsWritten =
std::fwrite(data, sizeof(float), numVars*numSegs, handle);
if (elementsWritten != numVars*numSegs){
std::cout << "Error" << std::endl;
}
fclose(handle);
handle = fopen("./sandbox.out", "rb");
float * read = new float[numSegs * numVars];
fseek(handle, 0, SEEK_SET);
fread(read, sizeof(float), numSegs*numVars, handle);
for (int i = 0; i < numVars * numSegs; ++i) {
std::cout << read[i] << std::endl;
}
}
It outputs:
0
0.23
0.46
0.69
0.92
1.15
0
0.23
0.46
0.69
0.92
1.15
When I load the file in a hexer, we get:
00 00 00 00 1f 85 6b 3e 1f 85 eb 3e d7 a3 30 3f
1f 85 6b 3f 33 33 93 3f -- -- -- -- -- -- -- --
I want to be calculate the float value from the decimal directly. For example: 1f 85 6b 3e
becomes 0.23 and 1f 85 eb 3e
becomes 0.46.
I've tried a few "binary to float" calculators on the web. When I put in the hexadecimal representation of the number, 0x1f856b3e
, in both calculators I get back 5.650511E-20
. But I thought the value should be 0.23 since I provided bytes 5-8 to the calculator and these bytes represent the second float written to disk.
What am I doing wrong?
This is an endianness issue if you for example switch:
1f 85 6b 3e
to:
3e 6b 85 1f
this will result in .23
when you convert it using one of your converters, for example I used IEEE 754 Converter and Floating Point to Hex Converter allows you to do double as well as single precision conversions.
来源:https://stackoverflow.com/questions/22567723/calculator-to-convert-binary-to-float-value-what-am-i-doing-wrong