std::random_shuffle produce the same result even though srand(time(0)) called once

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-01 04:27:42

random_shuffle() isn't actually specified to use rand() and so srand() may not have any impact. If you want to be sure, you should use one of the C++11 forms, random_shuffle(b, e, RNG) or shuffle(b, e, uRNG).

An alternative would be to use random_shuffle(indices.begin(), indices.end(), rand()); because apparently your implementation of random_shuffle() is not using rand().

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