In the following program body cosists of a vector of pointers. Points is a struct of x,y,z coordinates and a point_id. I believe as body is passed by const reference, the following step should produce an error. BUt the program is running without any problem. Can you please explain me why is this.
void readOutFile(const Body& body, int n){
....
body.bp[0]->points.push_back(Point_id(p,i));
}
Here's the issue:
body.bp[0]->points.push_back(Point_id(p,i));
^^
Indirecting through a pointer removes any constness; rather, the constness of the result is dependent on the type of the pointer.
T *t; // pointer to T: can modify t and (*t)
const T *t; // pointer to const-T: can modify t but not (*t)
T *const t; // const-pointer to T: can modify (*t) but not t
const T *const t; // const-pointer to const-T: can't modify either t or (*t)
This is one of best example which shows why data members should not be public
.
here, body
is constant hence its data members must not be changed, but in body.bp[0]->points
point is being changed which is not the member of Body
.Hence no const violation.
Only body
is constant.
body.bp[0]->points
is no way affected by the constantness of body
Yes, body
is constant. That means that no non-const member functions may be called, and no member variables be modified.
Neither is being done. The only member of body
used is body.bp[0]
, which is not changed either, but merely used to get at points
, which might or might not be constant...
Corrolary: Don't make data members public.
来源:https://stackoverflow.com/questions/10976702/c-passing-by-const-reference