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How to stop C++ console application from exiting immediately?
So im learning c++ and i was given this example and i wanted to run it. But i cannot get it to stay up, unless i change it. How do i get Microsoft visual 2010 to keep up the screen when it gets to the end of the program after I release it?
#include<iostream>
using namespace std;
int area(int length, int width); /* function declaration */
/* MAIN PROGRAM: */
int main()
{
int this_length, this_width;
cout << "Enter the length: "; /* <--- line 9 */
cin >> this_length;
cout << "Enter the width: ";
cin >> this_width;
cout << "\n"; /* <--- line 13 */
cout << "The area of a " << this_length << "x" << this_width;
cout << " rectangle is " << area(this_length, this_width);
return 0;
}
/* END OF MAIN PROGRAM */
/* FUNCTION TO CALCULATE AREA: */
int area(int length, int width) /* start of function definition */
{
int number;
number = length * width;
return number;
} /* end of function definition */
/* END OF FUNCTION */
In Visual C++ you can either:
- Put a breakpoint at the closing brace of
main
and run attached to the debugger (Debug -> Start Debugging). When the breakpoint is hit you will be able to view the console window. - Run detached from the debugger (Debug -> Start Without Debugging). When the application terminates, the console window will stay open with a "Press any key to continue..." prompt.
I usually use cin.getchar() to wait for a character.
Try adding system("PAUSE");
to the end of main
before the return
statement.
This executes the PAUSE system command which waits for a key to be pressed.
The easiest way is to wait for the user to press a key before returning from main.
You already have the answer in your code.. add another cin at the end of your program ;P user would have to press enter for program to continue and exit
来源:https://stackoverflow.com/questions/2725823/how-do-i-get-the-screen-to-pause