From the EMPLOYEE table, I want to group the amount of records(employees hired) AND also have the running TOTAL per day. The format of the input is like this:
rownum Hired_date_time 1 1/10/2012 11:00 2 1/10/2012 13:00 3 20/11/2012 10:00 4 20/11/2012 15:00 5 20/11/2012 16:00 6 30/12/2012 1:00
The desired output:
Hired_date.......Hired_per_day.........TOTAL_number_of_employees 1/10/2012 ...................2 ........2 20/11/2012 ..................3 ........5 30/12/2012 ..................1 ....... 6
No problem for the GROUPING PER DAY:
select trunc(Hired_date_time) as "Hired_date" ,
count(*) as "Hired_per_day"
from employee
group by trunc(Hired_date_time)
order by trunc(Hired_date_time);
Question: how can I have a running total (in last column) using the window function
select trunc(hired),
count(*) hired_today,
sum(count(*)) over (order by trunc(hired)) as running_total
from emp
group by trunc(hired)
select trunc(hire_date),
count(*) over (partition by trunc(hire_date)) as hired_per_day,
count(*) over (order by hire_date) as total_number_of_employees
from employee
order by trunc(hire_date)
来源:https://stackoverflow.com/questions/13702693/oracle-sql-running-total-and-daytotal-using-window-function