How to make iPhone vibrate using Swift?

问题

I need to make the iPhone vibrate, but I don\'t know how to do that in Swift. I know that in Objective-C, you just write:

import AudioToolbox
AudioServicesPlayAlertSound(kSystemSoundID_Vibrate);

But that is not working for me.

回答1:

Short example:

import UIKit
import AudioToolbox

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
        AudioServicesPlayAlertSound(SystemSoundID(kSystemSoundID_Vibrate))            
    }
}

load onto your phone and it will vibrate. You can put it in a function or IBAction as you wish.

回答2:

In iOS 10 on iPhone 7 or 7 Plus, try:

let generator = UIImpactFeedbackGenerator(style: .heavy)
generator.impactOccurred()

回答3:

Other vibration types:

import AudioToolbox

AudioServicesPlaySystemSound(1519) // Actuate "Peek" feedback (weak boom)
AudioServicesPlaySystemSound(1520) // Actuate "Pop" feedback (strong boom)
AudioServicesPlaySystemSound(1521) // Actuate "Nope" feedback (series of three weak booms)

More About Vibration - http://www.mikitamanko.com/blog/2017/01/29/haptic-feedback-with-uifeedbackgenerator/

回答4:

Swift 4.2 Updated

Just insert code below into your project.

Usage

Vibration.success.vibrate()

Source Code

import AVFoundation
import UIKit

    enum Vibration {
    case error
    case success
    case warning
    case light
    case medium
    case heavy
    case selection
    case oldSchool

    func vibrate() {

      switch self {
      case .error:
        let generator = UINotificationFeedbackGenerator()
        generator.notificationOccurred(.error)

      case .success:
        let generator = UINotificationFeedbackGenerator()
        generator.notificationOccurred(.success)

      case .warning:
        let generator = UINotificationFeedbackGenerator()
        generator.notificationOccurred(.warning)

      case .light:
        let generator = UIImpactFeedbackGenerator(style: .light)
        generator.impactOccurred()

      case .medium:
        let generator = UIImpactFeedbackGenerator(style: .medium)
        generator.impactOccurred()

      case .heavy:
        let generator = UIImpactFeedbackGenerator(style: .heavy)
        generator.impactOccurred()

      case .selection:
        let generator = UISelectionFeedbackGenerator()
        generator.selectionChanged()

      case .oldSchool:
        AudioServicesPlaySystemSound(SystemSoundID(kSystemSoundID_Vibrate))
      }

    }

}

回答5:

For iOS 10.0+ You can try UIFeedbackGenerator

Simple viewController above, just replace your view controller in your test "single view app"

import UIKit

class ViewController: UIViewController {

    var i = 0

    override func viewDidLoad() {
        super.viewDidLoad()

        let btn = UIButton()
        self.view.addSubview(btn)
        btn.translatesAutoresizingMaskIntoConstraints = false

        btn.widthAnchor.constraint(equalToConstant: 160).isActive = true
        btn.heightAnchor.constraint(equalToConstant: 160).isActive = true
        btn.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        btn.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true

        btn.setTitle("Tap me!", for: .normal)
        btn.setTitleColor(UIColor.red, for: .normal)
        btn.addTarget(self, action: #selector(tapped), for: .touchUpInside)
    }

    @objc func tapped() {
        i += 1
        print("Running \(i)")

        switch i {
        case 1:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.error)

        case 2:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.success)

        case 3:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.warning)

        case 4:
            let generator = UIImpactFeedbackGenerator(style: .light)
            generator.impactOccurred()
        case 5:
            let generator = UIImpactFeedbackGenerator(style: .medium)
            generator.impactOccurred()

        case 6:
            let generator = UIImpactFeedbackGenerator(style: .heavy)
            generator.impactOccurred()

        default:
            let generator = UISelectionFeedbackGenerator()
            generator.selectionChanged()
            i = 0
        }
    }
}

回答6:

We can do this in Xcode7.1

import UIKit
import AudioToolbox


class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()

        AudioServicesPlayAlertSound(kSystemSoundID_Vibrate)
    }
}

回答7:

Swift 4.2

 if #available(iOS 10.0, *) {
      UIImpactFeedbackGenerator(style: .light).impactOccurred()
   }

回答8:

You can vibrate the phone using either AudioServices or Haptic Feedback.

// AudioServices
AudioServicesPlayAlertSound(SystemSoundID(kSystemSoundID_Vibrate))

// Haptic Feedback
UIImpactFeedbackGenerator(style: .medium).impactOccurred()

Checkout my open source framework Haptica, it supports both Haptic Feedback, AudioServices and unique vibrations patterns. Works on Swift 4.2, Xcode 10

回答9:

AudioServicesPlaySystemSound(SystemSoundID(kSystemSoundID_Vibrate))

回答10:

import AudioToolbox

extension UIDevice {
    static func vibrate() {
        AudioServicesPlaySystemSound(kSystemSoundID_Vibrate)
    }
}

Now you can just call UIDevice.vibrate() as needed.

回答11:

UINotificationFeedbackGenerator available from iOS 10 and work with Haptic v2, we can check this:

  let feedbackSupportLevel = UIDevice.current.value(forKey: "_feedbackSupportLevel") as? Int
        if #available(iOS 10.0, *), let feedbackSupportLevel = feedbackSupportLevel, feedbackSupportLevel > 1 {
            do { // 1
                let generator = UIImpactFeedbackGenerator(style: .medium)
                generator.impactOccurred()
            }

            do { // or 2
                let generator = UINotificationFeedbackGenerator()
                generator.notificationOccurred(.success)
            }
        } else {
            AudioServicesPlayAlertSound(SystemSoundID(kSystemSoundID_Vibrate))
        }