问题
I have a property field in a class that is of type javax.xml.datatype.Duration
. It basically represents a time span (e.g. 4 hours and 34 minutes).
JPA is telling me it is an invalid type, which doesn't shock me.
Whats a good solution this? I could implement my own Duration class, but I don't know how to get JPA to "accept" it as a datatype.
回答1:
Whats a good solution this? I could implement my own Duration class, but I don't know how to get JPA to "accept" it as a datatype.
JPA does not support custom types so if you want to go this way you'll have to use a JPA extension from your provider. For example, Hibernate allows to define custom value types that you declare with @Type. Obviously, this will harm portability between providers which might be a concern. If not, then you know it is doable.
With standard JPA, the traditional approach would be to add another getter/setter pair which adapt the problematic property and perform conversion when accessed. I would use a Long
to store a duration:
public MyEntity implements Serializable {
private Long id;
private javax.xml.datatype.Duration duration;
@Id
@GeneratedValue
public Long getId() {
return this.id;
}
public void setId(Long id) {
this.id = id;
}
@Transient
public Duration getDuration() {
return this.duration;
}
public void setDuration(Duration duration) {
this.duration = duration;
}
public Long getDurationAsJpaCompatibleType() {
return MyXmlUtil.convertDurationToLong(this.duration);
}
public void setDurationAsJpaCompatibleType(Long duration) {
setDuration(MyXmlUtil.convertLongToDuration(duration));
}
}
回答2:
You can mirror the exact fields in the Duration class into your own custom class, but that might be overkill...I'm assuming you don't need that kind of duration flexibility/granularity.
So pick the fields you want, add them to your class, mark the class with the @Embeddable annotation, and add the proper JPA annotations to the fields (which I'm assuming will be simple ints).
In your entity that will store a duration, add the @Embedded annotation to the field or getter, whichever you typically use. From here you can further tweak the column definitions with @AttributeOverride.
回答3:
You could try joda-time hibernate. Refer to the available types that can be persisted. You could then use the joda Duration in the following way:
@Type(type="org.joda.time.contrib.hibernate.PersistentDuration")
private Duration startDateTime;
来源:https://stackoverflow.com/questions/2830089/how-to-map-duration-type-with-jpa