问题
This is the function in question. It calculates the Pearson correlation coefficient for p1 and p2, which is supposed to be a number between -1 and 1.
When I use this with real user data, it sometimes returns a number greater than 1, like in this example:
def sim_pearson(prefs,p1,p2):
si={}
for item in prefs[p1]:
if item in prefs[p2]: si[item]=1
if len(si)==0: return 0
n=len(si)
sum1=sum([prefs[p1][it] for it in si])
sum2=sum([prefs[p2][it] for it in si])
sum1Sq=sum([pow(prefs[p1][it],2) for it in si])
sum2Sq=sum([pow(prefs[p2][it],2) for it in si])
pSum=sum([prefs[p1][it]*prefs[p2][it] for it in si])
num=pSum-(sum1*sum2/n)
den=sqrt((sum1Sq-pow(sum1,2)/n)*(sum2Sq-pow(sum2,2)/n))
if den==0: return 0
r=num/den
return r
critics = {
'user1':{
'item1': 3,
'item2': 5,
'item3': 5,
},
'user2':{
'item1': 4,
'item2': 5,
'item3': 5,
}
}
print sim_pearson(critics, 'user1', 'user2', )
1.15470053838
回答1:
It looks like you may be unexpectedly using integer division. I made the following change and your function returned 1.0
:
num=pSum-(1.0*sum1*sum2/n)
den=sqrt((sum1Sq-1.0*pow(sum1,2)/n)*(sum2Sq-1.0*pow(sum2,2)/n))
See PEP 238 for more information on the division operator in Python. An alternate way of fixing your above code is:
from __future__ import division
回答2:
Well it took me a minute to read over the code but it seems if you change your input data to floats it will work
回答3:
Integer division is confusing it. It works if you make n
a float:
n=float(len(si))
回答4:
Well, I wasn't exactly able to find what's wrong with the logic in your function, so I just reimplemented it using the definition of Pearson coefficient:
from math import sqrt
def sim_pearson(p1,p2):
keys = set(p1) | set(p2)
n = len(keys)
a1 = sum(p1[it] for it in keys) / n
a2 = sum(p2[it] for it in keys) / n
# print(a1, a2)
sum1Sq = sum((p1[it] - a1) ** 2 for it in keys)
sum2Sq = sum((p2[it] - a2) ** 2 for it in keys)
num = sum((p1[it] - a1) * (p2[it] - a2) for it in keys)
den = sqrt(sum1Sq * sum2Sq)
# print(sum1Sq, sum2Sq, num, den)
return num / den
critics = {
'user1':{
'item1': 3,
'item2': 5,
'item3': 5,
},
'user2':{
'item1': 4,
'item2': 5,
'item3': 5,
}
}
assert 0.999 < sim_pearson(critics['user1'], critics['user1']) < 1.0001
print('Your example:', sim_pearson(critics['user1'], critics['user2']))
print('Another example:', sim_pearson({1: 1, 2: 2, 3: 3}, {1: 4, 2: 0, 3: 1}))
Note that in your example the Pearson coefficient is just 1.0
since vectors (-4/3, 2/3, 2/3) and (-2/3, 1/3, 1/3) are parallel.
来源:https://stackoverflow.com/questions/1423525/what-is-wrong-with-this-python-function-from-programming-collective-intelligenc