问题
Every looked at scope guard so far has a guard boolean variable. For example, see this discussion: The simplest and neatest c++11 ScopeGuard
But a simple guard works (gcc 4.9, clang 3.6.0):
template <class C>
struct finally_t : public C {
finally_t(C&& c): C(c) {}
~finally_t() { (*this)(); }
};
template <class C>
static finally_t<C> finally_create(C&& c) {
return std::forward<C>(c);
}
#define FINCAT_(a, b) a ## b
#define FINCAT(a, b) FINCAT_(a, b)
#define FINALLY(...) auto FINCAT(FINALY_, __LINE__) = \
finally_create([=](){ __VA_ARGS__ })
int main() {
int a = 1;
FINALLY( std::cout << "hello" << a << std::endl ; );
FINALLY( std::cout << "world" << a << std::endl ; );
return 0;
}
Why no temporary copies destructed? Is it dangerous to rely on this behavior?
回答1:
You're observing the effects of Copy Elision (or Move Elision, in this case). Copy Elision is not guaranteed / mandatory, but usually performed by major compilers even when compiling w/o optimizations. Try gcc's -fno-elide-constructors to see it "break": http://melpon.org/wandbox/permlink/B73EuYYKGYFMnJtR
来源:https://stackoverflow.com/questions/31922693/c-why-this-simple-scope-guard-works