问题
If I have a nested html (unordered) list that looks like this:
<ul>
<li><a href="Page1_Level1.html">Page1_Level1</a>
<ul>
<li><a href="Page1_Level2.html">Page1_Level2</a>
<ul>
<li><a href="Page1_Level3.html">Page1_Level3</a></li>
</ul>
<ul>
<li><a href="Page2_Level3.html">Page2_Level3</a></li>
</ul>
<ul>
<li><a href="Page3_Level3.html">Page3_Level3</a></li>
</ul>
</li>
</ul>
</li>
<li><a href="Page2_Level1.html">Page2_Level1</a>
<ul>
<li><a href="Page2_Level2.html">Page2_Level2</a></li>
</ul>
</li>
</ul>
How do I form a nested list out of it in Python? For example:
["Page1_Level1.html", ["Page1_Level2.html", ["Page1_Leve3.html", "Page2_Level3.html", "Page3_Level3.html"]], "Page2_Level1.html", ["Page2_Level2.html"]]
I presume libraries like Beautiful Soup and HTML Parser have facilities to do this, but I haven't been able it figure it out. Thanks for any help / pointers!
回答1:
You can take a recursive approach:
from pprint import pprint
from bs4 import BeautifulSoup
text = """your html goes here"""
def find_li(element):
return [{li.a['href']: find_li(li)}
for ul in element('ul', recursive=False)
for li in ul('li', recursive=False)]
soup = BeautifulSoup(text, 'html.parser')
data = find_li(soup)
pprint(data)
Prints:
[{u'Page1_Level1.html': [{u'Page1_Level2.html': [{u'Page1_Level3.html': []},
{u'Page2_Level3.html': []},
{u'Page3_Level3.html': []}]}]},
{u'Page2_Level1.html': [{u'Page2_Level2.html': []}]}]
FYI, here is why I had to use html.parser
here:
- Don't put html, head and body tags automatically, beautifulsoup
回答2:
It is an overview of a possible solution
# variable 'markup' contains the html string
from bs4 import BeautifulSoup
soup = BeautifulSoup(markup)
for a in soup.descendants:
# construct a nested list when going thru the descendants
print id(a), id(a.parent) if a.parent else None, a
来源:https://stackoverflow.com/questions/24216263/converting-html-list-to-nested-python-list