I have two forms. I need to open a second form with a button. When I open form2 I hide form1. However when I try to show form1 again from form2 with a button it doesn't work. My form1 code is:
Form2 form2 = new Form2();
form2.ShowDialog();
Inside form2 code:
Form1.ActiveForm.ShowDialog();
or
Form1.ActiveForm.Show();
or
form1.show(); (form1 doesn't exist in the current context)
doesn't work. I do not want to open a new form
Form1 form1 = new Form1();
form1.ShowDialog();
I want show the form which I hided before. Alternatively I can minimize it to taskbar
this.WindowState = FormWindowState.Minimized;
and maximize it from form2 again.
Form2.ActiveForm.WindowState = FormWindowState.Maximized;
however the way I am trying is again doesn't work. What is wrong with these ways?
You could try (on Form1 button click)
Hide();
Form2 form2 = new Form2();
form2.ShowDialog();
form2 = null;
Show();
or (it should work)
Hide();
using (Form2 form2 = new Form2())
form2.ShowDialog();
Show();
Preserve the instance of Form1
and use it to Show
or Hide
.
You can access Form1 from Form2 throught the Owner property if you show form2 like this:
form2.ShowDialog( form1 )
or like this:
form2.Show( form1 )
Notice this way you are not forced to use ShowDialog cause hide and show logic can be moved inside Form2
This method is the one that I find works the best for me
Primary Form
Form2 form2 = new Form2(this);
Secondary Form
private Form Form1
public Form2(Form Form1)
{
InitializeComponent();
this.Form1 = Form1;
Form1.Hide();
}
Later on when closing
private void btnClose_Click(object sender, EventArgs e)
{
Form1.Show();
this.Close();
}
来源:https://stackoverflow.com/questions/13233451/how-to-show-a-form-again-after-hiding-it