Tokenising a String containing empty tokens

问题

I have a seemingly simple problem of splitting a comma separated String into tokens, whereby the output should include empty tokens in cases where:

• The first character in the String is a comma.
• The last character in the String is a comma.
• Two consecutive commas occur.

For example, for the String: ",abd,def,,ghi," should yield the output: {"", "abd", "def", "", "ghi", ""}.

I have tried using String.split, Scanner and StringTokenizer for this but each gives a different undesired output (examples below). Can anyone suggest an elegant solution for this, preferably using JDK classes? Obviously I could code something myself but I feel like I'm missing something on one of the three approaches mentioned. Note that the delimiter is a fixed String although not necessarily a comma, nor a single character.

Example Code

import java.util.*;

public class Main12 {
  public static void main(String[] args) {
    String s = ",abd,def,,ghi,";
    String[] tokens = s.split(",");

    System.err.println("--- String.split Output ---");
    System.err.println(String.format("%s -> %s", s, Arrays.asList(tokens)));

    for (int i=0; i<tokens.length; ++i) {
      System.err.println(String.format("tokens[%d] = %s", i, tokens[i]));
    }

    System.err.println("--- Scanner Output ---");

    Scanner sc = new Scanner(s);
    sc.useDelimiter(",");
    while (sc.hasNext()) {
      System.err.println(sc.next());
    }

    System.err.println("--- StringTokenizer Output ---");

    StringTokenizer tok = new StringTokenizer(s, ",");
    while (tok.hasMoreTokens()) {
      System.err.println(tok.nextToken());
    }
  }
}

Output

$ java Main12
--- String.split Output ---
,abd,def,,ghi, -> [, abd, def, , ghi]
tokens[0] =
tokens[1] = abd
tokens[2] = def
tokens[3] =
tokens[4] = ghi
--- Scanner Output ---
abd
def

ghi
--- StringTokenizer Output ---
abd
def
ghi

回答1:

Pass a -1 to split as the limit argument:

String s = ",abd,def,,ghi,";
String[] tokens = s.split(",", -1);

Then your result array will include any trailing empty strings.

From the javadocs:

If [the limit] is non-positive then the pattern will be applied as many times as possible and the array can have any length. If [the limit] is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.

Calling split(regex) acts as if the limit argument is 0, so trailing empty strings are discarded.

来源：https://stackoverflow.com/questions/12395862/tokenising-a-string-containing-empty-tokens