问题
I am trying to create a webpage that has a gridview. this gridview is supposed to have a link like below
http://localhost/Test.aspx?code=123
when the user clicks one of the rows' link in gridview, it will open a blank page and display some result.
here is how I bind data to the gridview but I dont know how to set the link
protected void Page_Load(object sender, EventArgs e)
{
string firma_no = logoFrmNr.ToString().PadLeft(3, '0');
string active_period = logoFrmPeriod.PadLeft(2, '0');
SqlConnection conn = new SqlConnection(conStr);
string selectSql = @"SELECT
LOGICALREF,
CODE ,
DEFINITION_ ,
FROM
LG_CLFLINE";
SqlCommand cmd = new SqlCommand(selectSql, conn);
DataTable dt = new DataTable();
SqlDataAdapter da = new SqlDataAdapter(cmd);
da.Fill(dt);
GridView1.DataSource = dt;
GridView1.DataBind();
conn.Close();
}
here is the markup
<asp:GridView ID="GridView1" runat="server" EnableModelValidation="True">
</asp:GridView>
How can I make a link out of CODE column?
回答1:
There's a trick to this. The Hyperlinkcolumn won't work, because you can't format the link. You want to use a boundfield and format the text. Like so
<asp:GridView ID="GridView1" runat="server" EnableModelValidation="True">
<Columns>
<asp:BoundField DataField="Code" HtmlEncode="False" DataFormatString="<a target='_blank' href='Test.aspx?code={0}'>Link Text Goes here</a>" />
</Columns>
</asp:GridView>
Alternately, you can use a templatefield if you need to designate edit and insert templates.
回答2:
Add this to your Columns
definition in the markup for your grid view:
<asp:TemplateField HeaderText="Hyperlink">
<ItemTemplate>
<asp:HyperLink ID="HyperLink1" runat="server"
NavigateUrl='<%# Eval("CODE", @"http://localhost/Test.aspx?code={0}") %>'
Text='link to code'>
</asp:HyperLink>
</ItemTemplate>
</asp:TemplateField>
回答3:
to me it would be something like
<asp:DataGrid id="MyDataGrid"
GridLines="Both"
AutoGenerateColumns="false"
runat="server">
<HeaderStyle BackColor="#aaaadd"/>
<Columns>
<asp:HyperLinkColumn
HeaderText="Select an Item"
DataNavigateUrlField="code"
DataNavigateUrlFormatString="http://localhost/Test.aspx?code={0}"
Target="_blank"/>
</Columns>
</asp:DataGrid>
回答4:
You should be able to use a HyperLinkColumn in your markup.
HyperlinkColumn Documentation
来源:https://stackoverflow.com/questions/19798685/how-to-create-a-link-in-gridview-in-asp-net