How to get address of a Java Object? [duplicate]

问题

This question already has an answer here:

• Is there a way to get a reference address? [duplicate] 5 answers

Is there a way to get address of a Java object?

Where the question comes from?: At First, I read properties file and all the data from file was placed into table. Properties file can update. So, I want to listen that file. I listen an object using PropertyChangeSupport and PropertyChangeListener.

updatedStatus = new basit.data.MyString();
    updatedStatus.addPropertyChangeListener(new java.beans.PropertyChangeListener() {

        //After changes \"i\", we inform the table model about new value
            public void propertyChange(PropertyChangeEvent evt) {
                Object objec=evt.getNewValue();
                tableModel.setValueAt(objec.toString(), 0, 5);
            }
        });

If updatedStatus changes then i update table. MyString class have private String \"Value\". I want to listen properties file. So, it should make updatedStatus.value and String of Properties File equal at the same address. If i can do it, so i don\'t need to listen properties file.

updatedStatus.setValue(resourceMap.getString(\"HDI.Device.1.Name\"));

I tried to use StringBuffer, but i couldn\'t achieve it. That\'s why, I asked the question.

回答1:

Firstly - no, you can't get the address of an object in Java; at least, not pure Java with no debugging agent etc. The address can move over time, for one thing. You don't need it.

Secondly, it's slightly hard to follow your explanation but you certainly won't be able to get away without listening for changes to the file itself. Once you've loaded the file into a Properties object, any later changes to the file on disk won't be visible in that object unless you specifically reload it.

Basically you should listen for changes to the file (or poll it) and reload the file (either into a new Properties or overwriting the existing one) at that point. Quite whether you also need to listen for updates on the string container will depend on your application.

回答2:

we can get address of an object in memory. Well how? it is like that;

using sun.misc.Unsafe class in java.

create new Unsafe object and use the getAddress(Object); method and it will return a long value that is address.

and also there are many methods for this class.

you can change the values in this address using putInt(Object,long offset, int value) or like this method.(getting some value getnt(Object)).

Note: this class is really UNSAFE . if you make wrong things on your project, JVM will be stopped.

回答3:

System.identityHashCode(obj) delivers the next-best thing: a number unique for each object. It corresponds to the default Object.hashCode() implementation.

To quote the API: "As much as is reasonably practical, the hashCode method defined by class Object does return distinct integers for distinct objects. (This is typically implemented by converting the internal address of the object into an integer, but this implementation technique is not required by the JavaTM programming language.)".

回答4:

Look into Apache Commons Configuration. This library has support for dynamic reloading of (for example) property files. See here.

回答5:

The best way to observe if some file changes is IMHO to make a hash value with sha1 or mda5 and save the value in a cache. And you make a Thread that every minutes, seconds, depends how often you watch file changes, and make hash value over the file. So you can compare this two values and if the values are not equivalent so you can reload the new file.

回答6:

Java not like C/C++. in C++, you will often work with address (that C++ programmer has a concept call pointer). But, I afraid that not in Java. Java is very safe that prevent you to touch its address.

But, there other ways maybe same with your idea is use HashCode. HashCode of an object base on their address on HEAP.

来源：https://stackoverflow.com/questions/1360826/how-to-get-address-of-a-java-object