PHP: How to compare keys in one array with values in another, and return matches?

Question

I have the following two arrays:

$array_one = array('colorZero'=>'black', 'colorOne'=>'red', 'colorTwo'=>'green', 'colorThree'=>'blue', 'colorFour'=>'purple', 'colorFive'=>'golden');

$array_two = array('colorOne', 'colorTwo', 'colorThree');

I want an array from $array_one which only contains the key-value pairs whose keys are members of $array_two (either by making a new array or removing the rest of the elements from $array_one)

How can I do that?

I looked into array_diff and array_intersect, but they compare values with values, and not the values of one array with the keys of the other.

Answer 1

If I am understanding this correctly:

Returning a new array:

$array_new = [];
foreach($array_two as $key)
{
    if(array_key_exists($key, $array_one))
    {
        $array_new[$key] = $array_one[$key];
    }
}

Stripping from $array_one:

foreach($array_one as $key => $val)
{
    if(array_search($key, $array_two) === false)
    {
        unset($array_one[$key]);
    }
}

Answer 2

As of PHP 5.1 there is array_intersect_key (manual).

Just flip the second array from key=>value to value=>key with array_flip() and then compare keys.

So to compare OP's arrays, this would do:

$result = array_intersect_key( $array_one , array_flip( $array_two ) );

No need for any looping the arrays at all.

Answer 3

Tell me if it works:

for($i=0;$i<count($array_two);$i++){
  if($array_two[$i]==key($array_one)){
     $array_final[$array_two[$i]]=$array_one[$array_two[$i]];
     next($array_one);
  }
}

Answer 4

<?php 
$array_one = array('colorZero'=>'black', 'colorOne'=>'red', 'colorTwo'=>'green', 'colorThree'=>'blue', 'colorFour'=>'purple', 'colorFive'=>'golden');

$array_two = array('colorOne', 'colorTwo', 'colorThree');

print_r(array_intersect_key($array_one, array_flip($array_two))); 
?>