SELECT INTO and “Undeclared variable” error

问题

When I try to execute following query:

SELECT id_subscriber
  INTO newsletter_to_send
  FROM subscribers

I get an error:

#1327 - Undeclared variable: newsletter_to_send

What is wrong with that query ?

回答1:

INSERT ... SELECT

http://dev.mysql.com/doc/refman/5.1/en/insert-select.html

INSERT INTO newsletter_to_send
SELECT id_subscriber FROM subscribers

PS: are you sure you don't need in WHERE clause?

回答2:

MySQL does not support the SELECT ... INTO ... syntax.

You have to use the INSERT INTO ... SELECT .. syntax to accomplish there.

Read more here.. http://dev.mysql.com/doc/refman/5.0/en/insert-select.html

回答3:

I think you can follow my given way and hopefully you will be able to fix your problem.

At first use this sql command to create a new table where you want to take backup

CREATE TABLE destination_table_name LIKE source_table_name;

After then you can use this command to copy those data

INSERT INTO destination_table_name
SELECT * FROM source_table_name;

If you already have previous data in your Destination table , Firstly you can use this command

TRUNCATE TABLE destination_table_name;

Thanks By Md. Maruf Hossain

回答4:

CREATE TABLE table_name
AS  
SELECT ...(your select)

回答5:

MySQL does not support SELECT INTO [table]. It only supports SELECT INTO [variable] and can only do this one variable at a time.

What you can do, however is use the CREATE TABLE syntax with a SELECT like so:

CREATE TABLE bar ([column list]) SELECT * FROM foo;

回答6:

I tried working on this just now and this works for me:

CREATE TABLE New_Table_name
SELECT * FROM Original_Table_name;

回答7:

MySQL Server doesn't support the SELECT ... INTO TABLE Sybase SQL extension. Instead, MySQL Server supports the INSERT INTO ... SELECT standard SQL syntax, which is basically the same thing. See Section 12.2.5.1, “INSERT ... SELECT Syntax”.

Ref:- this

回答8:

mysql don't support SELECT ... INTO ... syntax,

if it's a new table, use CREATE TABLE ... SELECT ... syntax.

example:

CREATE TABLE artists_and_works
  SELECT artist.name, COUNT(work.artist_id) AS number_of_works
  FROM artist LEFT JOIN work ON artist.id = work.artist_id
  GROUP BY artist.id;

回答9:

If you want to create a new table as a Duplicate table.

CREATE TABLE WorkerClone LIKE Worker;   //only structure will show no data
CREATE TABLE WorkerClone Select * from  Worker; //DUPLICATE table created with all details.

回答10:

MySQL does not support SELECT INTO [table]. It only supports SELECT INTO [variable] and can only do this one variable at a time.

What you can do, however is use the CREATE TABLE syntax with a SELECT like so:

来源：https://stackoverflow.com/questions/2949653/select-into-and-undeclared-variable-error

标签

mysql

select-into