问题
When transmitting data, the Hamming code apparently allows you to recreate data that has been corrupted over the wire (an error correcting code).
How does this work and what are its limitations, if any?
Are there any better solutions for error correction (as opposed to retransmission)? Are there circumstances where retransmission is better?
回答1:
Let's try to explain it a bit:
We have a 3 bit number. The possibilities can be presented as a cube where each bit represent an axis. The eight possibilities are on the corners.
000 --------001
| \ | \
| 100---------101
| | | |
| | | |
010-|-------011 |
\| \|
110---------111
Each defect (for example 101 is read as 100) results in a shift on a line on the cube.
If we use two bits for the data and the third for a parity check (say for example even parity). We lose 4 datapoints. But it has the advantage that we can detect a single bit failure (which transforms an even count of 1's into an odd count of ones). The odd numbers are marked with a *. And we see that each odd (wrongly transmitted) word is cornered by even (rightfully transmitted) words. So if we receive 100, we can be sure it is wrong.
But (with a single bit failure) the correct representation could have been 000, 101 or 110. So we can detect something has been wrong but we cannot detect what was wrong:
000 -------*001
| \ | \
|*100---------101
| | | |
| | | |
*010-|-------011 |
\| \|
110--------*111
This is called a one bit error detecting code.
If we use another bit for checking and thus remove one for the data. We are left with 1 databit and 2 "check bits". In this case, lets assume 000 and 111 are valid data representations and the other six are not. Now we have an interesting situation if one bit is mangled during transport. If we send 000 and receive 010, we see that 010 has one valid neighbor (000) and two invalid ones (110 and 011). So now we know that we intended to send 000 and are able to correct that:
000 -------*001
| \ | \
|*100--------*101
| | | |
| | | |
*010-|------*011 |
\| \|
*110---------111
This is called a one bit error correcting code.
Please note that a one bit error correcting code is also a two bit error detecting code.
And to put it more generally.
If you have n check bits, you have a n bit error detecting code. If you have 2n check bits, you have a n bit error correcting code.
Of course you should order the "valid" codes so that they do not border on each other.
回答2:
Here's the really high-level overview.
Suppose that every time I send a message, I send thrie copies of the text.
Suppose that every time I send z message, I send three copies of the teyt.
Suppose that every tyme I send a message, I send three copies if the tezt.
By comparing characters and taking a simple majority vote in each position, you can correct single erroneous characters. However the cost of this scheme (amount of data that must be sent) is high, and it doesn't catch the unlikely-but-possible case of two errors in corresponding positions of different copies (as in the last word of the sample above).
Hamming codes (and other kinds of error-correcting codes, such as Reed-Solomon) are based on formulas that compute the extra data (rather than simple duplication). The added bits depend on combinations of the data bits in a way that errors in copying make detectable patterns of changes when the computation is repeated at the receiving end.
For sake of illustration, let's start with simple odd parity, adding a single bit to ensure that the total number of bits in a message is odd. So the message 10110110 becomes 101101100 (five 1s, no extra 1 needed) and the message 10010110 becomes 100101101 (four 1s, extra 1 needed). If you receive a message of 101101101 and see that there are six 1s, you know that there's an error, but don't know where. Suppose we add more parity bits, each on depending only on a part of the message, as illustrated below by copying the bits considered and using '-' for bits ignored:
10110110
1-1-0-1- => 0
-0-1-1-0 => 1
10--01-- => 1
--11--10 => 0
1011---- => 0
----0110 => 1
so the complete message is 10110110011001. Now suppose a transmission error changes the third bit in the message, so that it reads 10010110011001. When the receiver re-runs the error-checking computation, it fails to match:
10010110
1-0-0-1- => 1*
-0-1-1-0 => 1
10--01-- => 1
--01--10 => 1*
1001---- => 1*
----0110 => 1
and the check bits that fail to match are exactly the ones affected by the third data bit. This is not a real, robust error-correction scheme; it's just a sketch to illustrate how building in redundancy can help in identifying the exact nature of an error.
回答3:
You will find details on the way it works here
More general information about Error Corecting Codes is available here
回答4:
Information about Hamming code is available here and here.
As for suitability , this explains why :
Error-correcting codes like Hamming are suitable for simplex channels where no retransmission can be requested.
Error-detection plus retransmission is often preferred because it is more efficient.
For comparison, consider a channel with error rate of per bit. Let block size be 1000 bits.
To correct a single error (by Hamming code), 10 check bits per block are needed. To transmit 1000 blocks, 10,000 check bits (overhead) are required. To detect a single error, a single parity bit per block will suffice. To transmit 1000 blocks, only one exter block (due to the error rate of per bit) will have to be retransmitted, giving the overhead of only 2001 (= 1000 + 1001) bits.
回答5:
Hamming code is a mathematical trick to correct up to 4 lost bits in a serial transmission. It is also used in favour of the "parity bit" in modern memory chips.
Limitations are in the number of bits which can be restored, which is not more than 4. If more than 4 bits are lost, retransmission is required.
Different situations require different error correction techniques. Some of these techniques are listed in the other posts here.
回答6:
@GameCat and what about 2-bit error detecting code.
In this case lets say 111 has changed to 100. Then we can be sure that there are 2 bits wrong and we know this because the distance between 111 and 100 is 2 bits, and the distance of 000 and 100 is 1 bit. So if we know that there is 2-bit error we can be sure what is the right value.
来源：https://stackoverflow.com/questions/388599/how-does-the-hamming-code-work