问题
I'm having trouble getting sed to recognize both hyphen and underscore in its pattern string.
Does anyone know why
[a-z|A-Z|0-9|\-|_]
in the following example works like
[a-z|A-Z|0-9|_]
?
$ cat /tmp/sed_undescore_hypen
lkjdaslf lkjlsadjfl dfpasdiuy service-type = service-1; jaldkfjlasdjflk address = address1; kldjfladsf
lkjdaslf lkjlsadjfl dfasdf service-type = service_1; jaldkfjlasdjflk address = address1; kldjfladsf
$ sed 's/.*\(service-type = [a-z|A-Z|0-9|\-|_]*\);.*\(address = .*\);.*/\1 \2/g' /tmp/sed_undescore_hypen
lkjdaslf lkjlsadjfl dfpasdiuy service-type = service-1; jaldkfjlasdjflk address = address1; kldjfladsf
service-type = service_1 address = address1
$ sed 's/.*\(service-type = [a-z|A-Z|0-9|\-]*\);.*\(address = .*\);.*/\1 \2/g' /tmp/sed_undescore_hypen
service-type = service-1 address = address1
lkjdaslf lkjlsadjfl dfasdf service-type = service_1; jaldkfjlasdjflk address = address1; kldjfladsf
$ sed 's/.*\(service-type = [a-z|A-Z|0-9|_]*\);.*\(address = .*\);.*/\1 \2/g' /tmp/sed_undescore_hypen
lkjdaslf lkjlsadjfl dfpasdiuy service-type = service-1; jaldkfjlasdjflk address = address1; kldjfladsf
service-type = service_1 address = address1
回答1:
As mentioned, you don't need anything to separate your ranges in a bracket expression. All that will do is adding | to the characters matched by the expression.
Then, to add a hyphen, you can just put it as the first or last character in the expression:
[a-zA-Z0-9_-]
And finally, ranges like a-z don't necessarily mean abcd...xyz, depending on your locale. You could use a POSIX character class instead:
[[:alnum:]_-]
Where [:alnum:] corresponds to all alphanumeric characters of your locale. In the C locale, it corresponds to 0-9A-Za-z.
回答2:
You don't need to use | symbol in a regex character class to separate the characters. Perhaps try something like this ...
[a-zA-Z0-9\-_]
回答3:
$ sed 's/.*\(service-type = [a-z|A-Z|0-9|_-]*\);.*\(address = .*\);.*/\1 \2/g' sed_underscore_hypen.txt
service-type = service-1 address = address1
service-type = service_1 address = address1
pknga_000@miro MINGW64 ~/Documents
$ sed 's/.*\(service-type = [-a-z|A-Z|0-9|_]*\);.*\(address = .*\);.*/\1 \2/g' sed_underscore_hypen.txt
service-type = service-1 address = address1
service-type = service_1 address = address1
To match a hyphen in a character class, it must not be placed between two characters, otherwise it will be interpreted as a range operator. So to match a hyphen, place it at the beginning or end of the character class: and no escaping is necessary. See this answer for explanation: https://stackoverflow.com/a/4068725
来源：https://stackoverflow.com/questions/42743964/hyphen-and-underscore-not-compatible-in-sed