问题
As part of answering another question, I wanted to show that the insane level of optimisation of gcc
(-O3
) would basically strip out any variables that weren't used in main. The code was:
#include <stdio.h>
int main (void) {
char bing[71];
int x = 7;
bing[0] = 11;
return 0;
}
and the gcc -O3
output was:
.file "qq.c"
.text
.p2align 4,,15
.globl main
.type main, @function
main:
pushl %ebp
xorl %eax, %eax
movl %esp, %ebp
popl %ebp
ret
.size main, .-main
.ident "GCC: (Ubuntu 4.4.3-4ubuntu5) 4.4.3"
.section .note.GNU-stack,"",@progbits
Now I can see it's removed the local variables but there's still quite a bit of wastage in there. It seems to me that the entire:
pushl %ebp
xorl %eax, %eax
movl %esp, %ebp
popl %ebp
ret
section could be replaced with the simpler:
xorl %eax, %eax
ret
Does anyone have any idea why gcc
does not perform this optimisation? I know that would save very little for main
itself but, if this were done with normal functions as well, the effect of unnecessarily adjusting the stack pointer in a massive loop would be considerable.
The command used to generate the assembly was:
gcc -O3 -std=c99 -S qq.c
回答1:
You can enable that particular optimization with the -fomit-frame-pointer
compiler flag. Doing so makes debugging impossible on some machines and substantially more difficult on everything else, which is why it's usually disabled.
Although your GCC documentation may say that -fomit-frame-pointer
is enabled at various optimization levels, you'll likely find that that's not the case—you'll almost certainly have to explicitly enable it yourself.
回答2:
Turning on -fomit-frame-pointer
(source) should get rid of the extra stack manipulations.
GCC apparently left those in because they facilitate debugging (getting a stack trace when needed), although the docs note that -fomit-frame-pointer
is the default starting with GCC 4.6.
来源:https://stackoverflow.com/questions/5086230/is-the-gcc-insane-optimisation-level-o3-not-insane-enough