Call methods using jQuery Plugin design pattern

送分小仙女□ 提交于 2019-11-30 02:14:15

You'll have to get a reference to the class to call it's method with that plugin structure.

http://jsfiddle.net/D9JSQ/3/

$(document).ready(function() {
    var test = $("#foo").test().data("plugin_test");
    test.goodbye();
});

To do what you want, you must get rid of document.write to test it.

http://jsfiddle.net/D9JSQ/8/

;
(function($, window, document, undefined) {

    var pluginName = 'test';
    var defaults;

    function Plugin(element, options) {
        this.element = element;

        this.options = $.extend({}, defaults, options);

        this._name = pluginName;

        this.init();
    }

    Plugin.prototype = {
        init: function(name) {
            this.hello();
        },
        hello: function(name) {
            console.log('hello');
        },
        goodbye: function(name) {
            console.log('goodbye');
        }
    }


    $.fn[pluginName] = function(options) {
        return this.each(function() {
            if (!$.data(this, 'plugin_' + pluginName)) {
                $.data(this, 'plugin_' + pluginName, new Plugin(this, options));
            }
            else if ($.isFunction(Plugin.prototype[options])) {
                $.data(this, 'plugin_' + pluginName)[options]();
            }
        });
    }


})(jQuery, window, document);

$(document).ready(function() {
    $("#foo").test();
    $("#foo").test('goodbye');
});​

Look to the console for information.

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