How to pass common dictionary data to every page in django

I have a common data {the logged-in user's message number) to display on every page. I can simply pass to template as

dict={'messagenumber':5}
return render_to_response('template.html',dict,context_instance=RequestContext(request))

But it looks tedious if i have this dict data pass to very page. Is there an easier way to pass common data to every page?

Thanks

edited Sep 27 '11 at 12:41

Evgeny

3,6692 gold badges42 silver badges53 bronze badges

asked Jul 11 '10 at 2:13

icn

6,51831 gold badges87 silver badges126 bronze badges

add a comment |

3 Answers 3

active oldest votes

It blows me away how common this is. You want to use context processors my friend!

Very easy to create, like so:

def messagenumber_processor(request):
   return {'messagenumber': 5}

Since messagenumber is a dynamic variable based on the User, you could pull data from the database by fetching from request.user as you have full access to request within each context processor.

Then, add that to your TEMPLATE_CONTEXT_PROCESSORS within settings.py and you're all set :-) You can do any form of database operation or other logic within the context processor as well, try it out!

answered Jul 11 '10 at 2:21

Bartek

12.1k1 gold badge44 silver badges61 bronze badges

2

Two notes: 1) You'll need to have django.contrib.auth.middleware.AuthenticationMiddleware in your MIDDLEWARE_CLASSES setting in order for request.user to work. 2) Only templates rendered with django.template.RequestContext instances as context will have context processors applied. – Joseph Spiros Jul 11 '10 at 2:27
thanks, a couple of more questions. *)I can put this method in any where (in any my view files)? *)Adding this processor like 'myproject.myapp.myview.messagenumber_processor'? and *) How to call this data in template ? request.messagenumber_processor? – icn Jul 11 '10 at 2:33
@Joseph Valid points, which are stated in the links I posted, but thanks! @xlione You technically can put it anwyhere within your project, but it's recommended to place it in a context_processors.py for the application that these context processors will deal with. To call the data in your template, reference the dict you return in the context processor. E.g in my example if I put {{ messagenumber }} in my template, it would output 5 assuming I linked up my context processor all correctly. – Bartek Jul 11 '10 at 2:36
thanks again! it works like a charm! – icn Jul 11 '10 at 3:06

add a comment |

Just to save someone's time if new to django

settings.py

TEMPLATE_CONTEXT_PROCESSORS = ("django.contrib.auth.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.static",
"django.contrib.messages.context_processors.messages",
"home.context_processor.remote_ip")

in home application, create a python file called context_processor.py

in the context_processor.py add a function like this:

def remote_ip(request):
  return {'remote_ip': request.META['REMOTE_ADDR']}

use it in the templates like {{ remote_ip }}

来源：https://stackoverflow.com/questions/3221592/how-to-pass-common-dictionary-data-to-every-page-in-django

标签

pass

common