问题
I am trying to insert a few lines of text before a specific line, but keep getting sed errors when I try to add a new line character. My command looks like:
sed -r -i '/Line to insert after/ i Line one to insert \\
second new line to insert \\
third new line to insert' /etc/directory/somefile.txt
The error that is reported is:
sed: -e expression #1, char 77: unterminated `s' command
I've tried, using \n
, \\
(as in the example), no character at all, just moving the second line to the next line. I've also tried something like:
sed -r -i -e '/Line to insert after/ i Line one to insert'
-e 'second new line to insert'
-e 'third new line to insert' /etc/directory/somefile.txt
EDIT!: Apologies, I wanted the text inserted BEFORE the existing, not after!
回答1:
This should work:
sed -i '/Line to insert after/ i Line one to insert \
second new line to insert \
third new line to insert' file
回答2:
For anything other than simple substitutions on individual lines, use awk instead of sed for simplicity, clarity, robustness, etc., etc.
To insert before a line:
awk '
/Line to insert before/ {
print "Line one to insert"
print "second new line to insert"
print "third new line to insert"
}
{ print }
' /etc/directory/somefile.txt
To insert after a line:
awk '
{ print }
/Line to insert after/ {
print "Line one to insert"
print "second new line to insert"
print "third new line to insert"
}
' /etc/directory/somefile.txt
回答3:
When the lines to be inserted are the result of some command "mycmd" (like cat results.txt
or printf "%s\n" line{1..3}
), you can do
sed -i 's/Line to insert after/r' <(cmd) file
or
sed -i 's/Line to insert after/echo "&";cmd/e' file
The last command can be simple modified when you want to insert before some match.
回答4:
sed -i '/Line to insert after/ i\
Line one to insert\
second new line to insert\
third new line to insert' /etc/directory/somefile.txt
回答5:
This might work for you (GNU sed & Bash):
sed -i $'/Line to insert after/a\line1\\nline2\\nline3' file
回答6:
This ll works from the first line.. For eg: If you want to insert from 3rd line of a file, replace "1i" to "3i".
sed -i '1i line1'\\n'line2'\\n'line3' 1.txt
cat 1.txt
line1
line2
line3
Hai
回答7:
To be POSIX compliant and run in OS X, I used the following (single quoted line and empty line are for demonstration purposes):
sed -i "" "/[pattern]/i\\
line 1\\
line 2\\
\'line 3 with single quotes\`
\\
" <filename>
回答8:
This can be easily done with Perl also
$ cat MeanwhileInHell.txt
Iran|XXXXXX|Iranian
Iraq|YYYYYY|Iraquian
Saudi|ZZZZZ|Saudi is a Rich Country
USA|AAAAAA|USA is United States of America.
India|IIII|India got freedom from British.
Scot|SSSSS|Canada Mexio.
$ perl -pe 'BEGIN {$x="Line one to insert\nLine 2\nLine3\n"} $_=$x.$_ if /USA/ ' MeanwhileInHell.txt
Iran|XXXXXX|Iranian
Iraq|YYYYYY|Iraquian
Saudi|ZZZZZ|Saudi is a Rich Country
Line one to insert
Line 2
Line3
USA|AAAAAA|USA is United States of America.
India|IIII|India got freedom from British.
Scot|SSSSS|Canada Mexio.
$
回答9:
On MacOs I needed a few more things.
- Double backslash after the
i
- Empty quotes after the
-i
to specify no backup file - Leading backslashes to add leading whitespace
- Trailing double backslashes to add newlines
This code searches for the first instance of </plugins
in pom.xml and inserts another XML object immediately preceding it, separated by a newline character.
sed -i '' "/\<\/plugins/ i \\
\ <plugin>\\
\ <groupId>org.apache.maven.plugins</groupId>\\
\ <artifactId>maven-source-plugin</artifactId>\\
\ <executions>\\
\ <execution>\\
\ <id>attach-sources</id>\\
\ <goals>\\
\ <goal>jar</goal>\\
\ </goals>\\
\ </execution>\\
\ </executions>\\
\ </plugin>\\
" pom.xml
来源:https://stackoverflow.com/questions/32007152/insert-multiple-lines-of-text-before-specific-line-using-bash