Angular UI Grid: How to create a pre-populated dropdown menu for column filtering

假如想象 提交于 2019-11-29 16:42:43

问题


I am looking for some help regarding a feature of the Angular UI Grid. Specifically I am exploring filtering and while I was able to successfully implement sorting using free form text field(s) in my application as they do in the example on their site I would like some help finding a way to instead sort using a pre-populated drop-down menu for certain columns.

To clarify: By pre-populated I mean I would like the drop-down to be populated through my code. I am ok if the solution contains hard-coded data but my eventual goal would be to have the pre-population be comprised of the unique data value set of the column being sorted :)

I have seen this functionality in (for example) the Kendo UI (kendodropdownlist) but I am not interested in the price tag that comes along with that solution. I would like to stick with the Angular UI-grid mentioned (and linked) above. On StackOverflow I found one similar question but unfortunately it didn't seem to have gotten much traction. I am hoping that by giving a more detailed explanation of what I am looking for I will receive a more complete answer than I found there.

Here is what is currently in my controller:

var simpleMessagingApp = angular.module('MainAppCtrl', [ 'ngAnimate',
                                                         'ngTouch', 'ui.grid' ]);

simpleMessagingApp.controller('CacheTableCtrl', [ '$scope', '$http',
                                                  'uiGridConstants', function($scope, $http, uiGridConstants) {
    $scope.columns = [ {
        field : 'trans_detail',
        displayName : 'Transaction'
    }, {
        field : 'cust_name',
        displayName : 'Customer'
    }, {
        field : 'quantity',
        displayName : 'Quantity',
        filters : [ {
            condition : uiGridConstants.filter.GREATER_THAN,
            placeholder : 'greater than'
        }, {
            condition : uiGridConstants.filter.LESS_THAN,
            placeholder : 'less than'
        }
        ]
    }, {
        field : 'today_date',
        displayName : 'Current Date'
    } ];
    $scope.gridOptions1 = {
            enableSorting : true,
            enableFiltering : true,
            columnDefs : $scope.columns,
            onRegisterApi : function(gridApi) {
                $scope.grid1Api = gridApi;
            }
    };

    $http.get("../services/Coherence/Cache").success(function(data) {
        $scope.gridOptions1.data = data;
    });

} ]);

Below is the output - with the free-form text fields

For this specific example columns Customer, Quantity, and Current Date I would probably leave as free form drop downs, but I would really like to be able to filter using a pre-populated drop down for the transactions (and to have it in my toolbox for future projects of course!).

Thanks!


回答1:


You can use the built in selectOptions filter feature documented here: http://ui-grid.info/docs/#/tutorial/103_filtering

Example:

angular.module('exampleApp', ['ui.grid'])
  .controller('exampleCtrl', ['$scope', 'uiGridConstants', function($scope, uiGridConstants) {
    var animals = [
      { id: 1, type: 'Mammal', name: 'Elephant' },
      { id: 2, type: 'Reptile', name: 'Turtle' },
      { id: 3, type: 'Mammal', name: 'Human' }
    ];
                                                          
    var animalTypes = [
      { value: 'Mammal', label: 'Mammal' },
      { value: 'Reptile', label: 'Reptile'}
    ];
  
    $scope.animalGrid = {
      enableFiltering: true,
      columnDefs: [
        {
          name: 'type', 
          field: 'type', 
          filter: { selectOptions: animalTypes, type: uiGridConstants.filter.SELECT }
        },
        { name: 'name', name: 'name'}
      ],
      data: animals
    };
      
  }]);
<link href="http://ui-grid.info/release/ui-grid.css" rel="stylesheet" />
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<script src="http://ui-grid.info/release/ui-grid.js"></script>

<div ng-app="exampleApp">
  <div ng-controller="exampleCtrl">
    <h1>UI Grid Dropdown Filter Example</h1>
    <div ui-grid="animalGrid" class="grid"></div>
  </div>
</div>



回答2:


You can put a pulldown menu in the header via the headerCellTemplate in your columnDefs

  columnDefs: [
     {field:'myField',headerCellTempalte: 'mypulldowntemplate.html"...}
  ]

mypulldowntemplate.html

  <div ng-class="{ 'sortable': sortable }">
  <div class="ui-grid-vertical-bar">&nbsp;</div>
<div class="ui-grid-cell-contents {{col.headerClass}}" col-index="renderIndex">
    {{ col.displayName CUSTOM_FILTERS }}
    <br>
    <select ng-model="getExternalScopes().value[col.field]" ng-change="$event.stopPropagation();getExternalScopes().yourFilterFunction(col.field)">
    </select>
      
  ....

yourFilterFunction() can do whatever it is you want to have filtered. Perhaps just by setting some variables that you use in a custom filter you assign to the grid. You can find an example of setting a condition in your custom filter on the ui Grid Tutorial here http://ui-grid.info/docs/#/tutorial/103_filtering




回答3:


I had the same requirement recently.I have figured it out myself.Here is the steps i have followed.If you want to use filters in ui-grid you can use two approaches either use existing ui-grid custom_filters or created a header template and bind it into grid.There is a nice article that how can add drop downs in ui-grid.Based on that codes i have customized my code snippets.What i do is i have created custom template inside index.html.

<script type="text/ng-template" id="uiSelect">

      <ui-select-wrap>
        <label> Gender</label>
        <ui-select ng-model="MODEL_COL_FIELD" theme="selectize" ng-disabled="disabled" append-to-body="true" on-select="grid.appScope.filterTableBasedonDropDownSelect($item)">
          <ui-select-match placeholder="Select...">{{$select.selected}}</ui-select-match>
          <ui-select-choices repeat="item in col.colDef.editDropdownOptionsArray | filter: $select.search">
            <span>{{ item }}</span>
          </ui-select-choices>
        </ui-select>
      </ui-select-wrap>
    </script>

I have created function called filterTableBasedonDropDownSelect($item) it will handle the filtering logic.Note that when you call a function in ui-grid normal function declaration doesn't work. Because ui-grid has its own parent scope. so you should call your function like this.

on-select="grid.appScope.filterTableBasedonDropDownSelect($item)"

Then you can declare your function logic under controller.

$scope.filterTableBasedonDropDownSelect= function(item){
     $scope.gridOptions.data  = $filter('filter')($scope.jsonData,item, undefined);};

Here is my working example.

Hope this will help for someone.




回答4:


An extension to the accepted answer is something I just discovered through trial and error. You can use regular expressions in the selectOptions:

           columnDefs: [
            {
                name: 'starRating',
                headerCellClass: 'blue',
                headerTooltip: 'Star Rating',
                maxWidth: 100, 
                filter:
                {
                    type: uiGridConstants.filter.SELECT,
                    selectOptions: [
                        { value: /(THREE|FOUR|FIVE)/, label: 'Positive' },  // Here I wanted the user to be able to choose one option that would filter by several of the possible values in the data set
                        { value: /(ONE|TWO)/, label: 'Negative' },  // ...and Here
                        { value: 'ONE', label: '1' },
                        { value: 'TWO', label: '2' },
                        { value: 'THREE', label: '3' },
                        { value: 'FOUR', label: '4' },
                        { value: 'FIVE', label: '5' }
                    ]
                }
            },


来源:https://stackoverflow.com/questions/28097758/angular-ui-grid-how-to-create-a-pre-populated-dropdown-menu-for-column-filterin

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