javascript inheritance from multiple objects

蹲街弑〆低调 提交于 2019-11-29 12:45:21

Each object can only have one prototype, so if you want to add to the prototype after inheriting (copying) it, you have to expand it instead of assigning a new prototype. Example:

function Foo() {}

Foo.prototype = {
    x: function(){ alert('x'); },
    y: function(){ alert('y'); }
};

function Foo2() {}

Foo2.prototype = new Foo();
Foo2.prototype.z = function() { alert('z'); };

var a = new Foo();
a.x();
a.y();
var b = new Foo2();
b.x();
b.y();
b.z();

One solution would be:

function FooB() {}
var p = new Foo();
p.methodA = function(){...}
p.methodB = function(){...}
p.methodC = function(){...}
...

FooB.prototype = p;

Update: Regarding expanding with an existing object. You can always copy the existing properties of one object to another one:

FooB.prototype = new Foo();
var proto = {
     /*...*/
};

for(var prop in proto) {
    FooB.prototype[prop] = proto[prop];
}

As long as proto is a "plain" object (i.e. that does not inherit from another object) it is fine. Otherwise you might want to add if(proto.hasOwnProperty(prop)) to only add non-inherited properties.

You can use an extend function which copies the new members to the prototype object.

function FooB() {}
FooB.prototype = new FooA();

extend(FooB.prototype, {
    /* other methods here */
});

extend

/**
 * Copies members from an object to another object.
 * @param {Object} target the object to be copied onto
 * @param {Object} source the object to copy from
 * @param {Boolean} deep  whether the copy is deep or shallow
 */
function extend(target, source, deep) {
    for (var i in source) {
        if (deep || Object.hasOwnProperty.call(source, i)) {
            target[i] = source[i];
        }
    }
    return target;
}
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