Javascript event when mouse leaves browser window [duplicate]

妖精的绣舞 提交于 2019-11-29 12:40:07

问题


This question already has an answer here:

  • How can I detect when the mouse leaves the window? 17 answers

I'd like some Javascript code to run when the mouse leaves the browser window. I only need to support Safari (WebKit.)

I tried putting a mouseout handler on window. That handler is reliably called when the mouse leaves the browser window. But because of bubbling it is also called when the mouse moves between elements in the document. I can't figure out how to determine when the mouse has actually left the window and when it has only moved between elements.

When the mouse leaves the window, exactly one event is generated, and the target element appears to be the element the mouse was actually over. So checking to see if the target element is window or document doesn't work. And wrapping the whole page in an invisible containing div doesn't work either: if the div is invisible, then the mouse will never be over it, so nothing changes.

(The same thing happens if I put the handler on document or document.body, except that surprisingly document.body does not get mouseover/mouseout events when the mouse enters or leaves an empty part of the window, such as the empty vertical space created by absolutely positioning an element with bottom:0. For that space, document and window will get mouseover/mouseout events with the target being <html>, but document.body will not.)

Some ideas I had:

  • On each mouseout event, get the actual position of the mouse and see if it is in fact over the window. But I don't know if this is actually possible and it sounds like it would be tricky to eliminate all of the race conditions.
  • Also register a mouseover handler and detect cases where mouseout is not proceeded by (or followed shortly by a) a mouseover. But that would require a timer.

We use prototype.js so ideally I'd like to express the solution in terms of prototype's Event.observe, but I can figure that part out.

Thanks for any suggestions!


回答1:


SUMMARY: This can be done cleanly by checking the relatedTarget property during the mouseout event. If relatedTarget is not a child of document, then the mouse just left the window. It's easy to do yourself, but if you don't want to, some libraries (Mootools, future Prototype..) have baked-in functionality, and others (current Prototype) have extensions available. On IE, you could instead use mouseleave, which is a non-bubbling version of mouseout.

Details:

IE has events called mouseenter and mouseleave that are non-bubbling versions of mouseover and mouseout. Other browsers do not, but if they did, setting a mouseleave listener on window or document would do the trick.

A gentleman named Ken Snyder comes to the rescue:

On a mouseover, the relatedTarget property references the node from which the pointer came. On a mouseout, the relatedTarget property references the node to which the pointer went.On any event, the scope is the node to which the event is attached.When the relatedTarget is a not child of the currentTarget, a mouseover event is equivalent to a mouseenter event and a mouseout event is equivalent to a mouseleave event.

-- http://kendsnyder.com/archives/6-MouseEnter-and-MouseLeave.html

This makes it possible to implement mouseenter and mouseleave in other browsers. In fact, Ken provides same Prototype code to do so: http://kendsnyder.com/sandbox/enterleave/MouseEnterLeave.js

Duroth pointed out in comments that MooTools already includes something similar. (Thanks Duroth.) It sounds like the upcoming Prototype release (1.6.2) may include this functionality, but I can't find anything definite.




回答2:


Using only javascript, no prototype or jquery etc.

<html>
<head>
<script type="text/javascript">
  var mouseX = 0;
  var mouseY = 0;
  var counter = 0;
var mouseIsIn = true;
function wireEvent() {
window.addEventListener("mouseout",
    function(e){
        mouseX = e.pageX;
        mouseY = e.pageY;
        if ((mouseY >= 0 && mouseY <= window.innerHeight)
        && (mouseX >= 0 && mouseX <= window.innerWidth))
            return;
        //do something for mouse out
        counter++;
        mouseIsIn = false;
        document.getElementById('in_out').innerHTML='out' + counter;
    },
    false);
window.addEventListener("mouseover",
    function(e){
        if(mouseIsIn)
            return;
        //do something for mouse over
        counter++;
        mouseIsIn = true;
        document.getElementById('in_out').innerHTML='in' + counter;
    },
    false);
}
</script> 
</head>
<body onload="wireEvent();">
<div id="in_out">&nbsp;</div>
<div style="width:300px; height: 200px; background: red;">Dummy element</div>
</body>
</html>

UPDATE:
Added check for mouse position on mouseout triggered when moving in/out elements within the body. If it's within the window, mouseout event is not triggered.
Also introduced a flag for current status of mouse 'in' or 'out' using mouseIsIn. If it is true, mouseover will not trigger too.




回答3:


Perhaps you can set a listener for mouseover and mouseout document, body or some other element that wraps the entire document, and use that (by saving that it happened) as a trigger to determine whether it is a valid mouseout on window?

Failing that, your first idea (regarding position check) should work pretty good. Any event passes along the X/Y the event occured. If it is anything farther than height/width of the window, you left the actual window. If it is negative anything, you left the window. And, possibly, if it is exactly the height/width or exactly top: 0 or left: 0, then you left the window.




回答4:


When the mouse leaves any element, including the window, the window object will fire a mouseout event and pass the event object along with it.

One of the items in the event object is called toElement, which is a pointer to the element the mouse just entered when it left the old one. But when the mouse leaves the window, there is no such toElement so this item becomes null.

By testing whether or not this item is null on a mouseout event, you can tell if the mouse left the window. Here is the code:

window.onmouseout=function(event){ 
  if(event.toElement===null) console.log('the mouse left the window'); 
}



回答5:


Your problem comes from mouseout events being generated for elements inside the window, which then bubble up as described in the W3C events spec. You can check which element the event was actually fired on:

function mouseoutFunction(event) {
  event = event || window.event;
  var sender = event.srcElement || event.target;
}



回答6:


Here is my solution based on a timer. The timer here is basically used to give a chance for other event handlers (specifically, onmouseover) to execute before deciding that the mosue is out of the window. The timeout of 1ms (actually around 33ms, there is a minimum timer resolution) gives a little time for the mouseover to occur if it already hasn't.

var inWin=0;
window.onmouseout = function(e)
{
   inWin--;
   setTimeout(checkIfOut, 1);
}
window.onmouseover = function(e)
{
   inWin++;
}

function checkIfOut()
{
   if(!inWin)
   {
     //Yay! Mouse is out of the window (probably)
   }
}



回答7:


You can use onmouseout event on a window instead



来源:https://stackoverflow.com/questions/1672142/javascript-event-when-mouse-leaves-browser-window

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